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miskamm [114]
3 years ago
15

!NEED ANSWER ASAP!

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
5 0

Answer: 22.5% chance

Step-by-step explanation:

The number of students in total is 40 and 9 kids have chosen to play tag. 9 divided by 40 is .225 then we would multiply .225 with 100 to make it a percent.

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Jim’s football team started a play on the 50 yard line. On the first play, the team had a 7-yard gain. On the second play, they
lawyer [7]

This is a basic addition/subtraction question. It's saying that they started at the 50 yard line. On the play, they gained 7 yards. So, we'll add 50+7 = 57.

They're at the 57 yard line at this point. On the second play they lost 10 yards (how unfortunate). Thereby, we will subtract 57-10=47.

50 yards +7 yards. -10 yards.

The answer will be that they'll be on the 47 yard line on the next play.

5 0
3 years ago
Read 2 more answers
If helen travels 567 miles miles in 9 hours how far does she travel in one hour
Lynna [10]
To figure out how much she travels in one hour you just do 567÷9 so...
567÷9=63
Helen travels 63 miles per hour
5 0
3 years ago
If f(x) = x2 - 2x and g(x) = 6x + 4 for which value of x does (t +g)(x)=0​
Vinil7 [7]

Answer:

-2

Assumption:

Find the value of x such that (f+g)(x)=0.

Step-by-step explanation:

(f+g)(x)=0

f(x)+g(x)=0

(x^2-2x)+(6x+4)=0

Combine like terms:

x^2+4x+4=0

This is not too bad too factor on the left hand side since 2(2)=4 and 2+2=4.

(x+2)(x+2)=0

(x+2)^2=0

So we need to solve:

x+2=0

Subtract 2 on both sides:

x=-2

Let's check:

(f+g)(-2)

f(-2)+g(-2)

((-2)^2-2(-2))+(6(-2)+4)

(4+4)+(-12+4)

(8)+(-8)

0

0 was the desired output of (f+g)(x).

7 0
3 years ago
3, +5,9,-6, what is the total score of Jesse's hand?​
poizon [28]

Answer:

11

Step-by-step explanation:

3 + 5 = 8

8 + 9 = 17

17 - 6 = 11

4 0
3 years ago
Simplify each expression by combining like terms <br> 3x^-1 - 10x^-1
Dmitry_Shevchenko [17]

Answer:

-7/x

Step-by-step explanation:

first, you combine the terms together to get -7x^-1. you cant have negative exponents in the numerator so you move the x^-1 to the denominator. once it move its becomes positive then.

7 0
3 years ago
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