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3 years ago

A ratio of angel fish at a store is 5:4. the ratio of angel fish to goldfish is 4:3 . There are 60 clown fish at the pet store

Mathematics

2 answers:

dexar [7]3 years ago

6 0

Answer:

an i oop

Step-by-step explanation:

Aloiza [94]3 years ago

3 0

Answer:

So if there are 60 clownfish and the ratio from clownfish to angelfish is 5:4, this is the equation you are looking at:

5:4 = 60:?

To find ? you have to do 60 divided by 5 which equals 12 and multiply it times 4 to see how many angelfish there will be if there are 60 clownfish.

12 x 4 = 48

So if there are 60 clownfish there will be 48 angelfish. The ratio is 60:48

For the next one, same thing if there are 48 angelfish, then you are looking at this equation:

4:3 = 48:?

Again, we solve like we did the last one.

48 divided by 4= 12

3 x 12= 36

So, if there are 48 angelfish there will be 36 goldfish. The ratio is 48:36

I hope this helps:)

Step-by-step explanation:

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If X and Y are independent continuous positive random

Leni [432]

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b) $Z=XY$ can be computed in the same way; it has CDF

$F_Z(z)=P\left(X\le\dfrac zY\right)=\displaystyle\int_{\mathrm{supp}(Y)}P\left(X\le\frac zy\right)P(Y=y)\,\mathrm dy$

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$f_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}\frac1yf_X\left(\frac zy\right)f_Y(y)\,\mathrm dy$

Assuming $X\sim\mathrm{Exp}(\lambda_x)$ and $Y\sim\mathrm{Exp}(\lambda_y)$ , we have

$f_{Z=\frac XY}(z)=\displaystyle\int_0^\infty y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy$

$\implies f_{Z=\frac XY}(z)=\begin{cases}\frac{\lambda_x\lambda_y}{(\lambda_xz+\lambda_y)^2}&\text{for }z\ge0\\0&\text{otherwise}\end{cases}$

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$f_{Z=XY}(z)=\displaystyle\int_0^\infty\frac1y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy$

$\implies f_{Z=XY}(z)=\lambda_x\lambda_y\displaystyle\int_0^\infty\frac{e^{-\lambda_x\frac zy-\lambda_yy}}y\,\mathrm dy$

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