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xz_007 [3.2K]
2 years ago
6

Solve for x and y 100x + 50y = 200

Mathematics
1 answer:
Eva8 [605]2 years ago
8 0

Answer:

x = 1 and y = 2

Step-by-step explanation:

because 100(1) + 50(2) = 100 + 100 = 200


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nirvana33 [79]
Angle CBA is the right name because it's in between C and A
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I need help please. The question is already there. Tysm. 20 points.
Bess [88]

Answer:

$109 and 35%

Step-by-step explanation:

49.05 is the sale price and the discount is 55%. What’s the original price?

price/ 1- discount

49.05/ 1 - 0.55

49.05/ 0.45

109

for the other part

to find the discount subtract final price from original price

94 - 61.10 = 32.9

Which would be 35% in percent form.

5 0
2 years ago
Suppose that two teams play a series of games that ends when one of them has won ???? games. Also suppose that each game played
Musya8 [376]

Answer:

(a) E(X) = -2p² + 2p + 2; d²/dp² E(X) at p = 1/2 is less than 0

(b) 6p⁴ - 12p³ + 3p² + 3p + 3; d²/dp² E(X) at p = 1/2 is less than 0

Step-by-step explanation:

(a) when i = 2, the expected number of played games will be:

E(X) = 2[p² + (1-p)²] + 3[2p² (1-p) + 2p(1-p)²] = 2[p²+1-2p+p²] + 3[2p²-2p³+2p(1-2p+p²)] = 2[2p²-2p+1] + 3[2p² - 2p³+2p-4p²+2p³] =  4p²-4p+2-6p²+6p = -2p²+2p+2.

If p = 1/2, then:

d²/dp² E(X) = d/dp (-4p + 2) = -4 which is less than 0. Therefore, the E(X) is maximized.

(b) when i = 3;

E(X) = 3[p³ + (1-p)³] + 4[3p³(1-p) + 3p(1-p)³] + 5[6p³(1-p)² + 6p²(1-p)³]

Simplification and rearrangement lead to:

E(X) = 6p⁴-12p³+3p²+3p+3

if p = 1/2, then:

d²/dp² E(X) at p = 1/2 = d/dp (24p³-36p²+6p+3) = 72p²-72p+6 = 72(1/2)² - 72(1/2) +6 = 18 - 36 +8 = -10

Therefore, E(X) is maximized.

6 0
2 years ago
Explain how solving 8+2 can help you solve 80+20?
SVETLANKA909090 [29]
80+20 is ten times 8+2, if you factor out 10 from 80+20 we get 10(8+2)
5 0
2 years ago
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A swimmer swam 48 kilometers in d days. What is the value of d if the swimmer swam an average of 3.2 kilometers daily?
Semmy [17]
ANSWER:

d = 15

The swimmer swam 48 kilometres in 15 days.

STEP-BY-STEP EXPLANATION:

Let d = total no. of days the swimmer swam

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Average no. of kilometres swam daily = 3.2

THEREFORE:

3.2d = 48

d = 48 / 3.2

d = 15
4 0
3 years ago
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