Start by doing the binomial expansion of (x+y)^6 where x represents success. This is
(x^6y^0) + 6(x^5y^1) +15(x^4y^2) +20(x^3y^3) +15(x^2y^4) +6(x^1y^5) +(x^0y^6)
We are interested in the x^3y^3 term which represents exactly 3 sucesses. Since the probalbility of sucess and failure are both .5 we should be able to figure this out just using the coefficients of the terms which is
20/64 = .3125 which is 31.25%
Well, they're saying 9 with an exponet of 2 multiplied by something equals 27..... Hmmm.....
Um, wouldn’t it just be 9.5, 10.6, 11.7?
Answer:
$45
Step-by-step explanation:
(25*1)+(4*5)=
25+20=
45
