2 dollar coins+ 2 50 cent coins+ 3 25 cent coins+ 1 dime+ 1 nickel= $3.90
This could be done by shifting bases:
log (base a) b = [log (base 10) b]/[log (base 10) a], *note
it could be any other base ( it could be base e)
solving the given
problem: (log y/ log 2) + (log y/log 4) = 6
log y = 1.2041
y = 16
You just got to plug and solve...
a³-2bc
(2)³-2(-3)(4)
Solve and you get 32!