Answer:
Step-by-step explanation:
The given matrix equation is ;
![\frac{3}{2}\left[\begin{array}{cc}x&6\\8&4\end{array}\right] +y \left[\begin{array}{cc}1&4\\3&2\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%266%5C%5C8%264%5Cend%7Barray%7D%5Cright%5D%20%2By%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%264%5C%5C3%262%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dz%26z%5C%5C6z%262%5Cend%7Barray%7D%5Cright%5D)
We multiply the scalars to get;
![\left[\begin{array}{cc}\frac{3}{2}x&9\\12&6\end{array}\right] +\left[\begin{array}{cc}y&4y\\3y&2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Cfrac%7B3%7D%7B2%7Dx%269%5C%5C12%266%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dy%264y%5C%5C3y%262y%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dz%26z%5C%5C6z%262%5Cend%7Barray%7D%5Cright%5D)
We simplify to get;
![\left[\begin{array}{cc}\frac{3}{2}x+y&9+4y\\12+3y&6+2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Cfrac%7B3%7D%7B2%7Dx%2By%269%2B4y%5C%5C12%2B3y%266%2B2y%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dz%26z%5C%5C6z%262%5Cend%7Barray%7D%5Cright%5D)
By the equality property of matrices, we can write the following equations;
Also;
We substitute these values into equation (1) to find x.
A, C, E
Each of these match up as congruent parts.
Answer:
1
Step-by-step explanation:
If she has four $8 shirts, that costs $32, leaving her with $18 dollars, only enough for 1 pair of $10 shorts
C "<span>David’s equation is correct, because their spending will be multiplied by the number of months and then subtracted from their savings"</span> is the correct answer
Alright. So for:
a) 4(x+7)+3(x+5) Here we need to distribute the number outside of the parenthesis to the terms inside. So after distributing, we get 4x+28+3x+15. Then simplify this equation to 7x+43.
b) 3(2a+4b)+9(3a-2b) Same here. We distribute the number outside of the parenthesis to the terms inside. After distributing, we get 6a+12b+27a-18b. Then simplify to get 33a-6b.
c) 2(3u-5)-3(2u+1) As expected, same here. We distribute the number outside of the parenthesis. But here, we have a negative. Remember to distribute that as well. So we get 6u-10-6u-3. Then we simplify and get -13.
d) b(-5v-4)-2b(v+4) -_- Getting a bit boring... We distribute the variable from outside the parenthesis into the terms in the parenthesis. We get -5bv-4b-2bv-8b. Then simplify to get -3bv-12b.
**If you don't understand distributing, just let me know!
