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Aloiza [94]
3 years ago
15

Can anyone please help me? 2(9-4)+15=13

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
8 0
Distribute
18-8+15=13
combine like terms
10+15=13
25=13
???
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4 years ago
One minus five sixths equals
Gnesinka [82]

Answer: 0.16666666666

Step-by-step explanation:lol

5 0
3 years ago
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Use the graph to find the factorization of x^2 - 7x + 12.​
harkovskaia [24]

Answer:(x-3)(x-4)

Step-by-step explanation:Basically, the intercepts of the graph, 3 and 4, are when the graph is equal to zero, which is why is (x-3)(x-4) and not (x+3)(x+4).

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3 years ago
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Given a rectangle with length of (2x+9)cm and width of (3x+1)cm.Two squares, each with sides x cm is removed from the rectangle.
il63 [147K]

Answer: The length is 13cm and the width is 7cm

Step-by-step explanation:

For a rectangle of length L and width W, the area is:

A = W*L

In this case we have:

L = (2*x + 9) cm

W=(3*x + 1) cm

Then the area of the rectangle is:

A = (2*x + 9)*(3*x + 1) cm^2

A = (6*x^2 + 2*x + 27*x + 9) cm^2

A = (6*x^2 + 29*x + 9) cm^2

now we remove two squares with sides of x cm

The area of each one of these squares is (x cm)*(x cm)  = x^2 cm^2

Then the area of the figure will be:

area = (6*x^2 + 29*x + 9) cm^2 - (2*x^2 ) cm^2

area = (4*x^2 + 29*x + 9) cm^2

Now we know that the area of this shape is 83 cm^2, then we need to solve:

83 cm^2 = (4*x^2 + 29*x + 9) cm^2

0 =  (4*x^2 + 29*x + 9) cm^2 - 83 cm^2

0 = (4*x^2 + 29*x - 74) cm^2

Then we need to solve:

0 = 4*x^2 + 29*x - 74

Here we can use Bhaskara's equation, the solutions of this equation are given by:

x = \frac{-29 \pm \sqrt{29^2 - 4*4*(-74)}  }{2*4} = \frac{-29 \pm 45}{8}

Then the two solutions are:

x = (-29 - 45)/8 = -9.25  (for how the length and width are defined, we can not have x as a negative number, then this solution can be discarded).

The other solution is:

x = (-29 + 45)/8 = 2

x = 2

Then the length and width of the rectangle are:

Length = (2*2 + 9)cm = 13 cm

Width = (3*2 + 1)cm = 7cm

4 0
3 years ago
Solve c =(a² + 3b)/4 for b.<br><br>Bruv take all my points I literally blow at math :'(​
Sati [7]

Answer:

b=\frac{4c-a^{2} }{3}

Step-by-step explanation:

First: multiply both sides by 4. 4 times c is 4c and the other sides cancels out as you are doing the inverse operation of division

Then, you have 4c=a^{2} +3b

Subtract both sides by a squared

DO NOT TAKE THE SQUARE ROOT! This is because it is a squared plus 3b so you have to do the inverse of addition

From that you get 4c-a^{2} =3b

Finally, divide both sides by 3.

You get  b=\frac{4c-a^{2} }{3}

4 0
3 years ago
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