(-5, 3), (2, 1) what is the slope of the line that passes through the points

s2008m [1.1K]

Step-by-step explanation:

it clearly consists of 2 rectangles and 1 triangle (as you tried correctly to point out by drawing the separating lines).

we only need to calculate all 3 areas and add them up for the total.

the area of a rectangle is

length × width

so, in our 2 cases we have

6 × 2 = 12 km²

5 × (3 + 2 + 3) = 5×8 = 40 km²

the area of a triangle is

baseline × height / 2

in case of a right-angled triangle the 2 sides enclosing the 90° angle can be used as baseline and height.

so, in our case

6 × (5 + 2 + (3 + 2 + 3 - 2)) / 2 = 6×(7 + 6)/2 = 3×13 = 39 km²

in total, the whole area is

12 + 40 + 39 = 91 km²

4 0

2 years ago

4. If A = (-4, -5) and B = (-1, -10), what is the length of segment AB? Round your answer to the nearest hundredth.

HACTEHA [7]

Answer:

5.83095 or √34

Step-by-step explanation:

Find the difference between coordinates:

(x2-x1) = (-1 - -4) = 3

(y2-y1) = (-10 - -5) = -5

Square the results and sum them up:

(3)2 + (-5)2 = 9 + 25 = 34

Now Find the square root and that's your result:

Exact solution: √34 = √34

Approximate solution: 5.831

7 0

3 years ago

A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot

ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = $(x\times x)$

$=x^2$

The volume of the box is = area of the base × height

$=x^2h$

Therefore,

$x^2h=272$

$\Rightarrow h=\frac{272}{x^2}$

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

$=20x^2$ cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

$=10x^2$ cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

$=4xh\times 1.5$ cents

$=6xh$ cents

Total cost = $(20x^2+10x^2+6xh)$

$=30x^2+6xh$

Let

C $=30x^2+6xh$

Putting the value of h

$C=30x^2+6x\times \frac{272}{x^2}$

$\Rightarrow C=30x^2+\frac{1632}{x}$

Differentiating with respect to x

$C'=60x-\frac{1632}{x^2}$

Again differentiating with respect to x

$C''=60+\frac{3264}{x^3}$

Now set C'=0

$60x-\frac{1632}{x^2}=0$

$\Rightarrow 60x=\frac{1632}{x^2}$

$\Rightarrow x^3=\frac{1632}{60}$

$\Rightarrow x\approx 3$

Now $C''|_{x=3}=60+\frac{3264}{3^3}>0$

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is $=\frac{272}{3^2}$

=30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0

3 years ago

A student says that the x-intercept of the graph of × + 2y =5 is the point (0,5). Is the student correct or incorrect? Explain y

ivanzaharov [21]

The student is incorrect, the actual x-intercept is (5, 0).

<h3>Is the student correct or incorrect?</h3>

Here we have the equation:

x + 2y = 5

The student says that the x-intercept is the point (0, 5).

So if you look at the point you already can see that the student is incorrect, this is because the x-intercept always must have a y-value of 0. (the graph only intercepts the x-axis when y = 0).

So the point (0, 5) can't be an x-intercept.

For the given function:

x +2y = 5

The x-intercept is given by:

x + 2*0 = 5

x = 5

So it is (5 , 0).

If you want to learn more about x-intercepts:

brainly.com/question/3951754

#SPJ1

5 0

2 years ago

The graph shows the amount of money paid when purchasing bags of candy at the zoo:

s2008m [1.1K]

Answer:

$2 because the x axis is bags of candy 1 and the y axis is the cost 2 therefore 1 bag of candy cost $2 and 2 bags of candy cost $4

6 0

3 years ago