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3 years ago

There are 4 juice cartons and 9 milk cartons in the school refrigerator. What is the ratio of juice cartons to total cartons?

Mathematics

2 answers:

Rama09 [41]3 years ago

7 0

Ther is 4 juice cartons. 4+9=13. so it would be 4/13

garik1379 [7]3 years ago

6 0

<u>4:13</u> is the right answer

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masha68 [24]

64
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3 years ago

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What are equivalent ratios for 32/8

svet-max [94.6K]

Hey there!

32/8

= 32 ÷ 8 / 8 ÷ 8

= 4 / 1

Therefore, your answer should be: 4:1 or 4/1

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

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2 years ago

The perimeter of a triangle is 90 cm. The lengths of the sides of the triangle are in the ratios 3:5:7 Work out the length of th

qwelly [4]

Answer:

9cm 5:9

Step-by-step explanation:

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3 years ago

The monthly charge for a waste collection service is 1830 dollars for 100 kg of waste and 2460 dollars for 135 kg of waste. (a)

Ulleksa [173]

Answer:

$C=18w+30$

Step-by-step explanation:

We are given that The monthly charge for a waste collection service is 1830 dollars for 100 kg of waste

So, $(x_1,y_1)=(100,1830)$

We are also given that The monthly charge for a waste collection service is 2460 dollars for 135 kg of waste.

So, $(x_2,y_2)=(135,2460)$

We are supposed to find a linear model for the cost, C, of waste collection as a function of the number of kilograms, w.

So, we will use two point slope form :

Formula : $y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

Substitute the values

$y-1830=\frac{2460-1830}{135-100}(x-100)$

$y-1830=18(x-100)$

$y-1830=18x-1800$

$y=18x-1800+1830$

$y=18x+30$

y denotes the cost

x denotes the weight

So, Replace y with C and x with w

$C=18w+30$

So, a linear model for the cost, C, of waste collection as a function of the number of kilograms, w is $C=18w+30$

7 0

3 years ago

I have no idea how to do this, it is due in two days. Hopefully someone sees this before then.

elena-14-01-66 [18.8K]

Hello,

$m\ \widehat{ABC}=x\\m\ \widehat{BAC}=2*x\\\\So:\\ x+2x=90^o\\x=30^o\\$

$cos(30^o)=\dfrac{\sqrt{3} }{2} \\$

In the triangle ABC,

$cos(30^o)=\frac{BC}{BA} \\\\BA=\dfrac{cos(30^o)}{BC} \\\\BA=\frac{\dfrac{\sqrt{3} }{2} }{24} =16*\sqrt{3} \\\\$

$sin(30^o)=\dfrac{1 }{2} =\dfrac{AC}{AB} \\\\AC=\dfrac{1}{2} *16\sqrt{3} =8\sqrt{3}$

In the triangle ACB,

$cos(30^o)=\dfrac{AC}{AL} \\\\AL=\dfrac{8\sqrt{3} *2}{\sqrt{3} } =16\\$

6 0

3 years ago