Answer:
6
Step-by-step explanation:
y = x² - 6x + 11
Complete the square.
y = x² - 6x + 9 + 2
y = (x - 3)² + 2
a = 1, h = 3, k = 2
a + h + k = 6
Answer:
The probability that the aircraft is overload = 0.9999
Yes , The pilot has to be take strict action .
Step-by-step explanation:
P.S - The exact question is -
Given - Before every flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the aircraft. The aircraft can carry 37 passengers, and a flight has fuel and baggage that allows for a total passenger load of 6,216 lb. The pilot sees that the plane is full and all passengers are men. The aircraft will be overloaded if the mean weight of the passengers is greater than 6216/37 = 168 lb. Assume that weight of men are normally distributed with a mean of 182.7 lb and a standard deviation of 39.6.
To find - What is the probability that the aircraft is overloaded ?
Should the pilot take any action to correct for an overloaded aircraft ?
Proof -
Given that,
Mean, μ = 182.7
Standard Deviation, σ = 39.6
Now,
Let X be the Weight of the men
Now,
Probability that the aircraft is loaded be
P(X > 168 ) = P(
)
= P( z >
)
= P( z > -0.371)
= 1 - P ( z ≤ -0.371 )
= 1 - P( z > 0.371)
= 1 - 0.00010363
= 0.9999
⇒P(X > 168) = 0.9999
As the probability of weight overload = 0.9999
So, The pilot has to be take strict action .
Answer: 1.4 x 3 = 4.2
Step-by-step explanation:
1 x 3 = 3
.4 x 3 = 1.2
3 + 1.2 = 4.2
I'm almost 50% positive that it is B
The train will pass the jogger in 36 seconds.
Length of train = 120m
Speed of train = 45kmph
Distance by which the jogger is ahead of the engine of the train = 240 m
Speed of jogger = 9 kmph
To pass the jogger, the train will have to cover the length of the train and the distance by which the jogger is ahead of the engine of train.
Hence,
Distance = 120 + 240 = 360m
As,
Time = Distance/Speed
Relative speed of train w.r.t jogger = 45 - 9 = 36 kmph = 10 m/s
Hence,
Time = 360/10 = 36 seconds.
To learn more about train, here:-
brainly.com/question/21218609
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