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4 years ago

A Find the slope of the graph using the

Mathematics

1 answer:

Elodia [21]4 years ago

7 0

Answer: 2

Step-by-step explanation:

To find the slope, we use the formula $m=\frac{y_2-y_1}{x_2-x_1}$ . With the given points, we can directly plug them in and solve.

$m=\frac{10-2}{5-1} =\frac{8}{4}=2$

Now, we know that the slope is 2.

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An individual repeatedly attempts to pass a driving test. Suppose that the probability of passing the test with each attempt is

vladimir1956 [14]

Answer:

a) Our random variable X="number of tests taken until the individual passes" follows a geomteric distribution with probability of success p=0.25

For this case the probability mass function would be given by:

$P(X= k) = (1-p)^{k-1} p , k = 1,2,3,...$

b) $P(X \leq 3) = P(X=1) +P(X=2) +P(X=3)$

$P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25$

$P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875$

$P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406$

And adding the values we got:

$P(X \leq 3) =0.25+0.1875+0.1406=0.578$

c) $P(X \geq 5) = 1-P(X$

And we can find the individual probabilities:

$P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25$

$P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875$

$P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406$

$P(X= 4) = (1-0.25)^{4-1} *0.25 = 0.1055$

$P(X \geq 5) = 1-[0.25+0.1875+0.1406+0.1055]= 0.316$

Step-by-step explanation:

Previous concepts

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

$P(X=x)=(1-p)^{x-1} p$

Let X the random variable that measures the number of trials until the first success, we know that X follows this distribution:

$X\sim Geo (1-p)$

Part a

Our random variable X="number of tests taken until the individual passes" follows a geomteric distribution with probability of success p=0.25

For this case the probability mass function would be given by:

$P(X= k) = (1-p)^{k-1} p , k = 1,2,3,...$

Part b

We want this probability:

$P(X \leq 3) = P(X=1) +P(X=2) +P(X=3)$

We find the individual probabilities like this:

$P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25$

$P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875$

$P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406$

And adding the values we got:

$P(X \leq 3) =0.25+0.1875+0.1406=0.578$

Part c

For this case we want this probability:

$P(X \geq 5)$

And we can use the complement rule like this:

$P(X \geq 5) = 1-P(X$

And we can find the individual probabilities:

$P(X= 1) = (1-0.25)^{1-1} *0.25 = 0.25$

$P(X= 2) = (1-0.25)^{2-1} *0.25 = 0.1875$

$P(X= 3) = (1-0.25)^{3-1} *0.25 = 0.1406$

$P(X= 4) = (1-0.25)^{4-1} *0.25 = 0.1055$

$P(X \geq 5) = 1-[0.25+0.1875+0.1406+0.1055]= 0.316$

3 0

3 years ago

Simplify (4x − 6) − (5x + 1). (1 point)

jok3333 [9.3K]

Answer:

-x -7

Step-by-step explanation:

(4x − 6) − (5x + 1)

Distribute the minus sign

(4x − 6) − 5x - 1

Combine like terms

4x-5x -6-1

-x -7

6 0

3 years ago

Which of the following inequalities are correct?

Schach [20]

Answer:

Only C is correct

Step-by-step explanation:

59 is bigger than -59 not smaller so A is incorrect

0 is smaller than 76 not bigger do B is also incorrect

-76 is smaller than -59 according to number line so option C is correct

4 0

3 years ago

Read 2 more answers

40 green cars 20 silver if same # of green stayed the same how many more silver would need to be added so the ratio of green to

slega [8]

So, there will be 40 green cars. if we want the ratio to be 1:3, we will need there to b three times as many silver cars as green cars: 40*3=120.

we already have 20 silver, so we need to add 120-20, that is 100 silver cars!

4 0

3 years ago

Your family went on a road trip. They drove for 12 hours in one day. Your mom drove 5 / 6 of that time. How much of the time did

Viefleur [7K]

Answer:

Step-by-step explanation:

The first thing you do is:

12 % 6 = 2

Then you have to:

2 x 5 = 10

You divide the denominator then multiply it by the Numerator

7 0

4 years ago