which equation represents a proportional relationship that has a constant of proportionality equal to ?

Factor this polynomial expression.

tankabanditka [31]

Answer:

D: 3(x + 5)(x + 5)

Step-by-step explanation:

Try multiplying the last answer choice (D); the result is 3(x^2 + 10x + 25), or

3(x + 5)(x + 5).

5 0

3 years ago

-2/3(4x - 2) = 1/4(3x +1)

aleksley [76]

Answer:????

Step-by-step explanation:

i don’t know shister

8 0

3 years ago

You have a choice between 2 jobs, one pays $8.25/hr but requires you to spend $20 to get a uniform. The other pays $7.50/hr. At

Veronika [31]

Step-by-step explanation + Answer:

x = 1st job

y = 2nd job

x + y = 22......x = 22 - y

7x + 8.25y = 171.50

7(22 - y ) + 8.25y = 171.50

154 - 7y + 8.25y = 171.50

-7y + 8.25y = 171.50 - 154

1.25y = 17.50

y = 17.50 / 1.25

y = 14 <== 14 hrs at the 8.25 per hr job

x + y = 22

x + 14 = 22

x = 22 - 14

x = 8 <=== 8 hrs at the 7 per hr job

5 0

1 year ago

Help!! 50 points and brainliest!

Viktor [21]

Answer:

Second choice:

$x=2t$

$y=4t^2+4t-3$

Fifth choice:

$x=t+1$

$y=t^2+4t$

Step-by-step explanation:

Let's look at choice 1.

$x=t+1$

$y=t^2+2t$

I'm going to subtract 1 on both sides for the first equation giving me $x-1=t$ . I will replace the $t$ in the second equation with this substitution from equation 1.

$y=(x-1)^2+2(x-1)$

Expand using the distributive property and the identity $(u+v)^2=u^2+2uv+v^2$ :

$y=(x^2-2x+1)+(2x-2)$

$y=x^2+(-2x+2x)+(1-2)$

$y=x^2+0+-1$

$y=x^2$

So this not the desired result.

Let's look at choice 2.

$x=2t$

$y=4t^2+4t-3$

Solve the first equation for $t$ by dividing both sides by 2:

$t=\frac{x}{2}$ .

Let's plug this into equation 2:

$y=4(\frac{x}{2})^2+4(\frac{x}{2})-3$

$y=4(\frac{x^2}{4})+2x-3$

$y=x^2+2x-3$

This is the desired result.

Choice 3:

$x=t-3$

$y=t^2+2t$

Solve the first equation for $t$ by adding 3 on both sides:

$x+3=t$ .

Plug into second equation:

$y=(x+3)^2+2(x+3)$

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

$y=(x^2+6x+9)+(2x+6)$

$y=(x^2)+(6x+2x)+(9+6)$

$y=x^2+8x+15$

Not the desired result.

Choice 4:

$x=t^2$

$y=2t-3$

I'm going to solve the bottom equation for $t$ since I don't want to deal with square roots.

Add 3 on both sides:

$y+3=2t$

Divide both sides by 2:

$\frac{y+3}{2}=t$

Plug into equation 1:

$x=(\frac{y+3}{2})^2$

This is not the desired result because the $y$ variable will be squared now instead of the $x$ variable.

Choice 5:

$x=t+1$

$y=t^2+4t$

Solve the first equation for $t$ by subtracting 1 on both sides:

$x-1=t$ .

Plug into equation 2:

$y=(x-1)^2+4(x-1)$

Distribute and use the binomial square identity used earlier:

$y=(x^2-2x+1)+(4x-4)$

$y=(x^2)+(-2x+4x)+(1-4)$

$y=x^2+2x+-3$

$y=x^2+2x-3$ .

This is the desired result.

3 0

3 years ago

Read 2 more answers

5) Solve: 2.4p + 6 = 48

KatRina [158]

Answer:

p = 17.5

Step-by-step explanation:

This is the answer because:

1) First, we have to isolate x

2) To isolate x, first -6 from +6 and 48

+6 - 6 = 0

48 - 6 = 42

Equation: 2.4p = 42

3) Now we are left with 2.4p = 42

4) Next, divide 2.4 from 2.4 and 42

2.4/2.4 = 0

42/2.4 = 17.5

5) We are left with

p = 17.5

Therefore, the answer is p = 17.5

Hope this helps!

3 0

3 years ago