Question

Mandy throws a stone off a bridge into the river below. The stones height above the water in meters h(t) after t seconds is measured using function h(t) = -16t^2+32t+43. What is the initial height of the stone?

Answer 1

Answer:

The initial height of the stone is 43 meters.  

Step-by-step explanation:

We have, the height followed by stone as a function of time t is given by :

$h(t)= -16t^2+32t+43$

It is required to find the initial height of the stone. We know that initial height means height when t = 0. Putting t = 0 in above equation such that,

$h(0)= -16(0)^2+32(0)+43\\\\h=0+0+43\\\\h=43\ m$

So, the initial height of the stone is 43 meters.