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3 years ago

How is domain of the function f(x)=sinx restricted so that its inverse function exists?

Mathematics

1 answer:

Virty [35]3 years ago

8 0

Answer:

Correct answer: sin x ⇒D(x) : [- π/2, π/2] ; sin⁻¹x ⇒ CD(x) : [- π/2, π/2]

Step-by-step explanation:

In order for the function sin x to have an inverse function sin⁻¹x due to the monotony, the domain is taken D(x) : [- π/2, π/2] and the range of sin⁻¹x is CD(x) : [- π/2, π/2].

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Help me please!! Thank you!!!

kotykmax [81]

Answer:

the first one and the last one

Step-by-step explanation:

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2 years ago

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mars1129 [50]

Answer:

The 80% confidence interval for difference between two means is (0.85, 1.55).

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for difference between two means is:

$CI=(\bar x_{1}-\bar x_{2})\pm t_{\alpha/2,(n_{1}+n_{2}-2)}\times SE_{\bar x_{1}-\bar x_{2}}$

Given:

$\bar x_{1}=M_{1}=6.1\\\bar x_{2}=M_{2}=4.9\\SE_{\bar x_{1}-\bar x_{2}}=0.25$

Confidence level = 80%

$t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.20/2, (5+5-2)}=t_{0.10,8}=1.397$

*Use a <em>t</em>-table for the critical value.

Compute the 80% confidence interval for difference between two means as follows:

$CI=(6.1-4.9)\pm 1.397\times 0.25\\=1.2\pm 0.34925\\=(0.85075, 1.54925)\\\approx(0.85, 1.55)$

Thus, the 80% confidence interval for difference between two means is (0.85, 1.55).

3 0

3 years ago

Find the solution(s) to the system of equations represented in the graph.

jolli1 [7]

Answer:

(-3,0) and (0,3)

Step-by-step explanation:

The solution to the system of equation is where the two graphs intersect

The intersect at two points

(-3,0) and (0,3)

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3 years ago

Can someone help me please.

wolverine [178]

9514 1404 393

Answer:

$a=\sqrt{33}$

Step-by-step explanation:

The Pythagorean theorem tells you that the area of the square with side 'a' is the difference of the areas of the other two squares.

a² = 7² -4²

a² = 49 -16 = 33

a = √33

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3 years ago

Whitch expression is equivalent to p + (q + r )

fredd [130]

The answer will be p+q+r, or p+r+q, or q+p+r. Hope it help!

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3 years ago