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3 years ago

(3+2)x(3+4) need help

Mathematics

2 answers:

uranmaximum [27]3 years ago

4 0

Answer: 35

Step-by-step explanation: (3+2)x(3+4)

(5)x(7)

arsen [322]3 years ago

3 0

Answer:

Step-by-step explanation:

(3+2)(3+4)

5 times 7= 35

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A five-digit number starts with a number between 4-9 in the first position, with no restrictions on the remaining 4 digits. a

Maurinko [17]

Answer:

(a) $Pr = 0.3024$

(b) $Pr = 0.6976$

Step-by-step explanation:

Given

$Start = \{5,6,7,8\}$ i.e. between 4 and 9

$n(Start) =4$

$Digits = 5$

Solving (a): Probability that each of the 5 digit are different

Since there is no restriction;

The total possible selection is as follows:

$First\ digit = 4$ (i.e. any of the 4 start digits)

$Second\ digit = 10\\$ (i.e. any of the 10 digits 0 - 9)

$Third\ digit = 10$ (i.e. any of the 10 digits 0 - 9)

$Fourth\ digit = 10$ (i.e. any of the 10 digits 0 - 9)

$Fifth\ digit = 10$ (i.e. any of the 10 digits 0 - 9)

So, the total is:

$Total = 4 * 10 * 10 * 10 * 10$

$Total = 40000$

For selection that all digits are different, the selection is:

$First\ digit = 4$ (i.e. any of the 4 start digits)

$Second\ digit = 9$ (i.e. any of the remaining 9)

$Third\ digit = 8$ (i.e. any of the remaining 8)

$Fourth\ digit = 7$ (i.e. any of the remaining 7)

$Fifth\ digit = 6$ (i.e. any of the remaining 6)

So:

$Selection =4 * 9 * 8 * 7 * 6$

$Selection =12096$

So, the probability is:

$Pr = \frac{Selection}{Total}$

$Pr = \frac{12096}{40000}$

$Pr = 0.3024$

Solving (b): At least 1 repeated digit

The probability calculated in (a) is the all digits are different i.e. P(None)

So, using laws of complement

We have:

$P(At\ least\ 1) = 1 - P(None)$

So, we have:

$Pr= 1 - 0.3024$

$Pr = 0.6976$

Solving (c): An expression to model the probability.

<em>Using (a) as a point of reference, we have;</em>

$Pr = \frac{Selection}{Total}$

Where

$Selection =4 * 9 * 8 * 7 * 6$ ---- for selection of 5 i.e. n = 5

$Total = 4 * 10 * 10 * 10 * 10$

$Selection =4 * 9 * 8 * 7 * 6$

This can be rewritten as:

$Selection = 4 * ^9P_4$

4 can be expressed as: 5 - 1

So, we have:

$Selection = (5-1) *^9P_{5-1}$

Substitute n for 5

$Selection = (n-1) *^9P_{n-1}$

$Selection = (n-1)^9P_{n-1}$

$Total = 4 * 10 * 10 * 10 * 10$

This can be rewritten as:

$Total = 4 * 10^4$

$Total = (5-1) * 10^{5-1}$

$Total = (n-1) * 10^{n-1}$

$Total = (n-1) 10^{n-1}$

So, the expression is:

$Pr = \frac{(n-1)^9P_{n-1}}{(n-1)10^{n-1}}$

$Pr = \frac{^9P_{n-1}}{10^{n-1}}$

<em>Where n represents the digit number</em>

5 0

3 years ago

A play was attended by 173 people. Adult tickets were $5 each and children paid $3 for each ticket the total revenue was $703. H

mr_godi [17]

The answer to this is 10545.

3 0

3 years ago

Read 2 more answers

At the end of year 1, Boller Co. had an ending balance in allowance for uncollectible accounts of $30,000. During year 2, Boller

Masja [62]

Answer:

$34,000

Step-by-step explanation:

First they had 30,000

Then wrote off 40,000

So balance is 30,000 - 40,000 = -10,000

Now, they want 8% of 300,000 as uncollectible. So that would be

0.08 * 300,000 = 24,000

Thus, to bring the balance to 24,000 [balance is -10,000], how much would they need to add?? Let it be x:

-10,000 + x = 24,000

x = 24,000 + 10,000 = $34,000

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4 years ago

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bixtya [17]

Answer:

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3 years ago

What is 38475 x 304944 ? My teacher won't let me use a calculator!

bearhunter [10]

Answer:

1,059,680,400

Step-by-step explanation:

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