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3 years ago

Multiply. (Use photo). Enter your answer in simplest radical form.

Mathematics

1 answer:

IrinaK [193]3 years ago

7 0

Answer:

72√2

Step-by-step explanation:

3√2 × 2√8 × √3 × √6

The above can be simplified as follow:

3√2 × 2√8 × √3 × √6

Recall

a√c × b√d = (a×b)√(c×d)

3√2 × 2√8 × √3 × √6 = (3×2)√(2×8×3×6)

= 6√288

Recall

288 = 144 × 2

6√288 = 6√(144 × 2)

Recall

√(a×b) = √a × √b

6√(144 × 2) = 6 × √144 × √2

= 6 × 12 × √2

= 72√2

Therefore,

3√2 × 2√8 × √3 × √6 = 72√2

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Draw a number line and mark all described points on it. Numbers that are both larger than –2 and smaller than 3.

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Answer:

The numbers larger than -2 and smaller than 3 are -1,0,1,2.

Step-by-step explanation:

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3 years ago

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mina [271]

6^3

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3 years ago

D/d{cosec^-1(1+x²/2x)} is equal to

SIZIF [17.4K]

Step-by-step explanation:

$\large\underline{\sf{Solution-}}$

$\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

Let assume that

$\rm :\longmapsto\:y = {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

We know,

$\boxed{\tt{ {cosec}^{ - 1}x = {sin}^{ - 1}\bigg( \dfrac{1}{x} \bigg)}}$

So, using this, we get

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2x}{1 + {x}^{2} } \bigg)$

Now, we use Method of Substitution, So we substitute

$\red{\rm :\longmapsto\:x = tanz \: \rm\implies \:z = {tan}^{ - 1}x}$

So, above expression can be rewritten as

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2tanz}{1 + {tan}^{2} z} \bigg)$

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( sin2z \bigg)$

$\rm\implies \:y = 2z$

$\bf\implies \:y = 2 {tan}^{ - 1}x$

So,

$\bf\implies \: {cosec}^{ - 1}\bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = 2 {tan}^{ - 1}x$

Thus,

$\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

$\rm \: = \: \dfrac{d}{dx}(2 {tan}^{ - 1}x)$

$\rm \: = \: 2 \: \dfrac{d}{dx}( {tan}^{ - 1}x)$

$\rm \: = \: 2 \times \dfrac{1}{1 + {x}^{2} }$

$\rm \: = \: \dfrac{2}{1 + {x}^{2} }$

<u>Hence, </u>

$\purple{\rm :\longmapsto\:\boxed{\tt{ \dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = \frac{2}{1 + {x}^{2} }}}}$

<u>Hence, Option (d) is </u><u>correct.</u>

6 0

2 years ago

-6u+7=-29 what does u equal

Marizza181 [45]

Answer: <em>u = 6</em>

Step-by-step explanation: To solve for <em>u</em> in the equation you see here, we must first isolate the term containing <em>u</em> which in this problem is -6u.

Since 7 is being added to -6u, we subtract 7 from both sides of the equation to isolate the -6u. On the left side of the equation, the +7 and -7 cancel out and on the right side of the equation, -29 - 7 is -36 so we have -6u = -36.

Now we can finish things off by just dividing both sides of the equation by -6. On the left the -6's cancel and on the right -36 divided by -6 is 6.

So u = 6 and you can check your answer by 6 back in for <em>u</em> in the original equation shown below in italics.

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3 years ago

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TEA [102]

<h3>Answer:</h3>

A (graph below)

Not appropriate
Appropriate
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<h3>Step-by-step explanation:</h3>

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3 years ago

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