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Harlamova29_29 [7]
3 years ago
7

I need help on this!!

Mathematics
2 answers:
Mama L [17]3 years ago
7 0
Answer:
What’s the question

Explanation:

VMariaS [17]3 years ago
5 0

Answer: Picture pls

Step-by-step explanation:

.

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Please help quickly <br><br> AB=AD and BC=DC<br> x=?
Arisa [49]

Answer:

x = 110

Step-by-step explanation:

measure of abd is 35, meaning adb is also 35.

so dab + abd + adb is 180

=> x + 35 + 35 = 180

=> x + 70 = 180

=> x = 180-70

=> x = 110

110 degrees is the value of x.  

8 0
2 years ago
Solve the inequality -4x &lt; 66
Alex73 [517]

Answer:

x >-33/2

Step-by-step explanation:

-4x < 66

Divide each side by -4, remembering to flip the inequality

-4x/-4 > 66/-4

x >-33/2

6 0
3 years ago
Read 2 more answers
Describe the difference between total surface area and lateral surface area
Diano4ka-milaya [45]

Answer:

The total surface area of a solid is the sum of the areas of all of the faces or surfaces that enclose the solid, the lateral surface area of a solid is the surface area of the solid without the bases

7 0
3 years ago
Read 2 more answers
M∠1=119∘ and m∠2=61∘.<br> What is m∠3?
marin [14]

Answer:

m∠3 = 119°

Step-by-step explanation:

All the angles must equal 360° when added together. You have two known angles that are right next to each other. If you add m∠1 and m∠2, 119 + 61, it is equal to 180°. This means that m∠3 and m∠4 must be equal to 180° as well and since there are only two lines, it is safe to assume that opposing angles are the same so m∠1 = m∠3 and m∠2 = m∠4.

4 0
2 years ago
Read 2 more answers
C2d3 has a solubility product constant of 9.14×10−9. what is the molar solubility of c2d3?
UkoKoshka [18]
The correct answer for the question that is being presented above is this one:

We need to express the ksp expression of C2D3
<span>C2D3
= (2x)2(3x)3
= 108x5 </span>

<span>Then set that equation equal to your solubility constant </span>

<span>9.14x10-9 = 108x5 </span>
<span>x = 9.67x10-3 
</span>
<span>So the molar solubility is 9.67x10-3</span>
4 0
3 years ago
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