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7nadin3 [17]
4 years ago
13

0=-20.5x+16.35x-0.1245

Mathematics
1 answer:
Pachacha [2.7K]4 years ago
7 0

The value of x in the given equation -20.5x+16.35x -0.1245 = 0\\ is 0.03

<u>Step-by-step explanation:</u>

The given equation is that -20.5x+16.35x -0.1245 = 0\\

<u>The steps to be followed to solve the equation are :</u>

Add the like terms together to reduce the equation in a simplified form.

Here, there are two x terms and they must be reduced to a single term.

For this, add the both terms together so that the equation is simplified into one x term and a constant term.

⇒ (-20.5x+16.35x) - 0.1245 = 0

⇒ 4.15x-0.1245 = 0

To eliminate the constant term on the left side of the equation, add 0.1245 on both sides.

⇒ 4.15x -0.1245+0.1245 = 0.1245

⇒ 4.15x = 0.1245

Now, the equation is further simplified by dividing 4.15 on both sides,

⇒ 4.15x / 4.15 = 0.1245/4.15

⇒ x = 0.03

Therefore, the value of x is 0.03

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Step-by-step explanation:

Given

\sqrt{128a^{6}b^{13}}

Required

Solve

\sqrt{128a^{6}b^{13}}

The expression can be split to:

\sqrt{128a^{6}b^{13}} = \sqrt{128} * \sqrt{a^{6}} * \sqrt{b^{13}}

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\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12 + 1}}

\sqrt{128a^{6}b^{13}} = \sqrt{64} * \sqrt{2} * \sqrt{a^{6}} * \sqrt{b^{12}} * \sqrt{b}

So, we have:

\sqrt{128a^{6}b^{13}} = 8 * \sqrt{2} * a^{6/2} * b^{12/2} * \sqrt{b}

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Rewrite as:

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\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6}* \sqrt{2b}

\sqrt{128a^{6}b^{13}} = 8 a^{3} b^{6} \sqrt{2b}

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