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Elena L [17]
3 years ago
6

What is the percent of 34

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
5 0

Answer:

I would be glad to help you if you give me some more informatio.

Step-by-step explanation:

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Describe the number line of the compound inequality
Anna35 [415]

Answer:

5<x<6

Step-by-step explanation:

4 0
3 years ago
Help now ____________[_
marta [7]
10 x 5 = 50
4 x 7 = 28
3 x 4 = 12 12/2=6

50+28+6= 84 square inches
6 0
3 years ago
Find the probability that an SRS of 36 babies will have an average birthweight of over 3.9 kg. Write your answer as a decimal. R
Jlenok [28]

Complete question :

The birthweight of newborn babies is Normally distributed with a mean of 3.96 kg and a standard deviation of 0.53 kg. Find the probability that an SRS of 36 babies will have an average birthweight of over 3.9 kg. Write your answer as a decimal. Round your answer to two places after the decimal

Answer:

0.75151

Step-by-step explanation:

Given that :

Mean weight (m) = 3.96kg

Standard deviation (σ) = 0.53kg

Sample size (n) = 36

Probability of average weight over 3.9

P(x > 3.9)

Using the z relation :

Zscore = (x - m) / (σ / √n)

Zscore = (3.9 - 3.96) / (0.53 / √36)

Zscore = - 0.06 / 0.0883333

Zscore = −0.679245

Using the Z probability calculator :

P(Z > - 0.679245) = 0.75151

= 0.75151

3 0
3 years ago
Isaac keeps track of the miles per gallon his car gets per week. He has accumulated the following data:
ipn [44]

we know that

A <u>geometric sequence</u> is a sequence of numbers in which the ratio between consecutive terms is constant

so

Let

a1=24 \ a2=24.48\ a3=24.97\ a4=25.47

\frac{a2}{a1} = \frac{24.48}{24}= 1.02

a2=a1*1.02

\frac{a3}{a2} = \frac{24.97}{24.48}= 1.02

a3=a2*1.02

\frac{a4}{a3} = \frac{25.47}{24.97}= 1.02

a4=a3*1.02

therefore

The common ratio is equal to 1.02

<u>the answer is</u>

The common ratio is 1.02

4 0
3 years ago
Read 2 more answers
Find all positive integer values of c that make x^2+6x+c factorable
densk [106]
It's factorable when c  ∈ {5,8,9}
6 0
4 years ago
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