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2 years ago

Max sprints forward 10 feet and then stops and sprints

Mathematics

1 answer:

Dafna11 [192]2 years ago

8 0

Answer:

10-15= -5

Step-by-step explanation:

max is 5 feet behind from where he started

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What expression is equivalent to -9(-5z-2)-7

trapecia [35]

Answer: 45z + 11

Explanation:

-9(-5z - 2) - 7
= 45z + 18 - 7
= 45z + 11

4 0

2 years ago

The drama club is printing t-shirts for its members. The printing company charges a certain amount for each shirt plus a setup f

Setler [38]

Answer: $7.

Step-by-step explanation:

It is given that the printing company charges a certain amount for each shirt plus a setup fee of $40.

Let x be the cost of each t-shirt.

There are 21 students in the drama club. So, total cost of 21 t-shirts is

$\text{Total cos}=40+21x$

It is given that the t-shirt order costs a total of $187.

$40+21x=187$

$21x=187-40$

$21x=147$

Divide both sides by 21.

$x=\dfrac{147}{21}$

$x=7$

Therefore, the cost of each t-shirt is $7.

4 0

2 years ago

The relation described in this statement can be classified as which of the following? The total distance traveled and the time s

Rzqust [24]

The relation described in this statement can be classified as both a relation and a function.

7 0

2 years ago

Identify the slope (m) and y-intercept (b) of each linear equation. 52. 3x+4y=24

nekit [7.7K]

Answer:

Step-by-step explanation:

[1] 3x - 4y = -24

[2] -x - 16y = -52

Graphic Representation of the Equations :

-4y + 3x = -24 -16y - x = -52

Solve by Substitution :

// Solve equation [2] for the variable x

[2] x = -16y + 52

// Plug this in for variable x in equation [1]

[1] 3•(-16y+52) - 4y = -24

[1] - 52y = -180

// Solve equation [1] for the variable y

[1] 52y = 180

[1] y = 45/13

// By now we know this much :

x = -16y+52

y = 45/13

// Use the y value to solve for x

x = -16(45/13)+52 = -44/13

Solution :

{x,y} = {-44/13,45/13}

8 0

2 years ago

What theorem shows that TPN ≅ TQM?

melisa1 [442]

Note: Consider the side of first triangle is TQ instead of TA.

Given:

Triangles TQM and TPN which share vertex T.

$TQ\cong TP,TM\cong TN$

To find:

The theorem which shows that $\Delta TPN\cong TQM$ .

Solution:

In triangle TQM and TPN,

$TQ\cong TP$ [Given]

$\angle QTM\cong \angle PTN$ [Given]

$TM\cong TN$ [Given]

Since two sides and their including angle are congruent in both triangles, therefore both triangles are congruent by SAS postulate.

$\Delta TPN\cong TQM$ [SAS]

Therefore, the correct option is C.

5 0

2 years ago