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gogolik [260]
3 years ago
10

Please help I suck at math

Mathematics
1 answer:
Volgvan3 years ago
6 0
I think it is the last one.
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What is –3 2/3 · (–2 1/4 )?
algol [13]
-3\frac{2}{3}\cdot\left(-2\frac{1}4{}\right)=\\--------------------\\negative\ number\ multiply\ by\ negative\ number\ is\ a\ positive\ number\\--------------------\\-3\frac{2}{3}\cdot\left(-2\frac{1}4{}\right)=3\frac{2}{3}\cdot2\frac{1}{4}=\\------------------------------\\

if you want to multiply mixed numbers you need to turn them into improper fractions

3\frac{2}{3}\cdot2\frac{1}{4}=\frac{3\cdot3+2}{3}\cdot\frac{2\cdot4+1}{4}=\frac{9+2}{3}\cdot\frac{8+1}{4}=\frac{11}{3}\cdot\frac{9}{4}=\frac{11}{1}\cdot\frac{3}{4}=\frac{11\cdot3}{1\cdot4}\\\center\boxed{=\frac{33}{4}=8\frac{1}{4}}

6 0
3 years ago
A bakery makes 40 different flavors of muffins. 25% of the flavors have chocolate as one of the ingredients. How many flavors ha
Likurg_2 [28]

Answer:

10

Step-by-step explanation:

because 25%of 40 is 10

6 0
3 years ago
Read 2 more answers
Can someone help me plz I need it
Vladimir [108]
Constant is y =5
Cubic is y = x^3
Souare root is y = x ^2
I don’t know the rest sorry
8 0
3 years ago
How do I solve this?
sergij07 [2.7K]

I would say m∠TBS= 52°

SV=15

m∠TCV=52° as well

this is my best guess

wish I could help more sorry:(

6 0
4 years ago
Anita invested $6000, some at 5% and the rest at 6%. If the yearly income is $337.50, what is the amount invested at each rate?
Pepsi [2]

Let the amount invested with 5% interest be x

Therefore, the amount invested with 6% interest will be (6000-x)

It is given that the total interest earned yearly is $337.5. Thus, the equation of interest will be:

\frac{5}{100}x+\frac{6}{100}(6000-x)=337.5

Multiplying both sides by 100 we get:

5x+6(6000-x)=33750

5x+36000-6x=33750

Subtracting both sides by 36000 we get:

-x=-2250

\therefore x=2250

Thus, the amount invested at 5% is $2250

Therefore, the amount invested at 6% will be $(6000-2250)=$3750

6 0
3 years ago
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