Answer:
yes
Step-by-step explanation:
please take a better picture
There's this many Packages and this many cans in each package right? All you have to do is multiply the number of cans and the number of packages to get the total number of cans.
For the cost is the same thing. If you know the cost is this much, multiply the amount of packages×The cost of each package which will give you the total cost. Good luck
* Craig's answer is not reasonable because to add fractions the denominators must be the same.
** Total distance = 5/8 + 1/2 = 5/8 + 4/8 = 9/8 miles
*** Using the line number to prove the answer:
The line number that represents the problem is in the attached figure.
while the distance between 0 and 1 divided to 8 sections
to represent (5/8) count 5 sections from zero ⇒⇒⇒ point (a)
and to represent (1/2) it is the midpoint between 0 and 1 which mean it is 4 sections but it will be counted from point (a) so, adding 4 sections to point (a) the result will be the point (b)
So, counting from 0 to point (b) will give us 9 sections
and while one section represents (1/8)
So the total distance will be 9 * (1/8) = 9/8 which is agree with the result obtained before
7) Draw a quadrilateral with 1 pair of parallel side. What special quadrilateral have you drawn?
Properties of a quadrilateral:
1) has four sides or edges
2) has four vertices or corners
3) interior angles add up to 360°
US definition: A trapezoid is a quadrilateral that has 1 pair of parallel sides.
UK definition: A trapezium is a quadrilateral that has 1 pair of parallel sides.
Answer:
The solution of the differential equation is .
Step-by-step explanation:
The first step is to take Laplace transform in both sides of the differential equation. As usual, we denote the Laplace transform of as . Then,
In the last step we use that and .
Notice that our differential equations becomes an algebraic equation for , which is more simple to solve.
In the expression we have obtained, we can write in terms of :
which is equivalent to
.
Now, we make a partial fraction decomposition for the term . Thus,
.
Substituting the above value into the expression for we get
) in both hands of the above expression. Recall that . So,
.
To obtain this we have used the following identities that can be found in any table of Laplace transforms