Let's say that h(x) = x+3. To find the inverse switch h(x) and x and call h(x) by its inverse name
. so f(x) = x - 3.
so h(f(x)) = (x - 3) + 3 = x what we did is plug f(x) in for x which is the inverse of h(x). The answer is h(f(x)) =x.
We see that the differences are -9, -3, +3, and +9. Thus, we see that the function is symmetric about x=2 (I'm assuming the five values correspond to x=0, 1, 2, 3, 4) and increases at a rate similar to (x-2) squared. With that in mind, we classify this function as a parabola, as the standard form of a parabola (y=a(x-h)^2 + k) shows similar growth to this function.
Answer:
im new how does this work??
Step-by-step explanation:
Im sorry i can’t help you but you can use photomath and also Aaa HANGE
Positive 3
It’s positive three
