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2 years ago

3(x+2)^2+7 in standard form

Mathematics

1 answer:

Lady bird [3.3K]2 years ago

4 0

Answer:-2x^2+3x-7=0

Step-by-step explanation:

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Need to know the population in 2015

Margarita [4]

$\bf P=1110.9e^{kt}\quad 
\begin{cases}
P=1200 &\textit{in thousands}\\
t=2 &\textit{in 2002}
\end{cases}\implies 1200=1110.9e^{k2}
\\\\\\
\cfrac{1200}{1110.9}=e^{2k}\implies ln\left( \frac{1200}{1110.9} \right)=ln(e^{2k})\implies ln\left( \frac{1200}{1110.9} \right)=2k
\\\\\\
\cfrac{ln\left( \frac{1200}{1110.9} \right)}{2}=k\implies 0.0385755\approx k\implies 0.0386\approx k\\\\
-------------------------------\\\\$

$\bf P=1110.9e^{0.0386t}\qquad 
\begin{cases}
t=14\\
\textit{year 2015}
\end{cases}\implies P=1110.9e^{0.0386\cdot 14}
\\\\\\
P\approx 1907.0747\implies about\ 1,907,075\textit{ once rounded up}$

3 0

2 years ago

There are 26 students in Jenna's class. Jenna brought in 16 cupcakes. Which equation can be used to find the number of cupcakes

Olin [163]

Answer:

Step-by-step explanation:

16+n=26

26-16=n

4 0

2 years ago

Read 2 more answers

Is the product of 3√ and 2.8 is a rational number acquisition?

svetlana [45]

Answer:

It is not rational

Step-by-step explanation:

Given

$\sqrt 3 * 2.8$

Required

Rational or Irrational

$\sqrt 3 * 2.8$

$\sqrt 3 =1.73205$

So, we have:

$\sqrt 3 * 2.8 = 1.73205 * 2.8$

$\sqrt 3 * 2.8 = 4.84974$

<em>The result of the product: 4.84974 is not rational because it can not be represented as a fraction of two integers.</em>

5 0

2 years ago

LM is the midsegment of trapezoid ABCD. AB= x + 8, LM = 4x + 3, and DC = 187. What is the value of x?

beks73 [17]

$\frac{|DC|+|AB|}{2}=|LM|\\\\|AB|=x+8;\ |LM|=4x+3;\ |DC|=187\\\\substitute:\\\\\frac{187+x+8}{2}=4x+3\ \ \ \ /\cdot2\\\\195+x=8x+6\ \ \ /-195;\ /-8x\\\\-7x=-189\ \ \ /:7\\\\\underline{\underline{x=27}}$

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2 years ago

Whats 560,233,827,222,400 X 2 my computer doesnt respond <br> also whats 8,591,715,599,360 X 2

levacccp [35]

The first answer is 1120,467,654,444,800

the second answer is 17,183,431,198,720

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2 years ago