Answer:
C
Step-by-step explanation:
the answer is C sense that makes the most sense with the problem
Answer:
The weight of the water in the pool is approximately 60,000 lb·f
Step-by-step explanation:
The details of the swimming pool are;
The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet
The depth of the pool = 5 feet
The density of the water in the pool = 60 pounds per cubic foot
From the question, we have;
The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g
The volume of water in the pool = Cross-sectional area × Depth
∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³
Acceleration due to gravity, g ≈ 32.09 ft./s²
∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N
266,196.089 N ≈ 60,000 lb·f
The weight of the water in the pool ≈ 60,000 lb·f
300, because 8x20=160 so 1 ounces= 20 calories
15x20=300
We have to find on the graph which is f ( - 3 ).
This is the quadratic function which passes through the points: ( - 6, - 3 ), ( 0 , - 3 ) and ( - 3, - 9 ).
Also we can conclude that the point ( - 3, - 9 ) is the minimum value of this function. So : f ( - 3 ) = - 9.
Answer:
A ) - 9.
Answer: The answer is 1/2
