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3 years ago

4. x^2+13x=-42

1 answer:

8 0

$x^2+13x=-42\ \ \ |+42\\\\x^2+13x+42=0\\\\x^2+6x+7x+42=0\\\\x(x+6)+7(x+6)=0\\\\(x+6)(x+7)=0\iff x+6=0\ \vee\ x+7=0\\\\x=-6\ \vee\ x=-7$

Anaswer: a. x = -6 or x = -7

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A triangle has one side that lies along the line y=1/4x and another that lies along the line y=-1/4x. Which of the following poi

mestny [16]

Answer:

We know that our triangle has one side along the line:

y = (1/4)*x

And other side along the line:

y = -(1/4)*x.

Now, we want to find the vertex.

And we know that the vertex is the point where the two sides conect, so the vertex must be a common point of both lines.

Then we have:

y = (1/4)*x = -(1/4)*x

x = -x

The only solution to that equation is x = 0.

now we evaluate our lines in x = 0 and get:

y = (1/4)*0 = 0

y = -(1/4)*0 = 0

Then the lines intersect in the point (0, 0)

Then the vertex must be in the point (0, 0)

4 0

2 years ago

Please help me fast i am giving 14 points for 5 questions. (Geometry) Thank you so much!

algol13

1 ) Area of the rectangle:
A = L x W
L = √(2² + 2²) = √8 = 2√2
W = √(6² + 6²) = √72 = 6√2
A = 2√2 x 6√2 = 24 units²
2 ) Area of a triangle:
RQ = 2 + 4 = 6 units
h = 4 units
A = ( 6 * 4 ) / 2 = 12 units²
3 ) The perimeter of Δ ABC:
AB = √(3² + 4²) = √25 = 5 units
BC = √(1² + 1²) = √2 = 1.4 units
AC = √(3² + 4²) = √25 = 5 units
P = 5 + 1.4 + 5 = 11.4 units
4 ) Area of the figure ( approx.):
A ≈ ( 8 * 8) - 6.25 - 8 - 2.5 ≈ 47.25
Answer: C ) 50 ft²
5 ) Area under the curve:
A ≈ 0.5 * 3 + 0.5 * 3.5 + 0.5 * 4 + 0.5 * 4.5 + 0.5 * 5 + 0.5 * 4.5 + 0.5 * 4 +
+ 0.5 * 3 ≈ 0.5 * 31.5 ≈ 15.6
Answer: B ) 15 units²

6 0

2 years ago

Helppppppppppppppppppppppppp

KiRa [710]

<h2>Answer:</h2><h2>52.7856 cm</h2>

Solution,

diameter=16.8 cm

radius=8.4 cm

Circumference of circle=2 pi r

 = 2*3.142*8.4

 =52.7856 cm

Hope it helps

Good luck on your assignment

5 0

2 years ago

Write an expression involving exponents to represent the shaded area in square inches of the diagram than use that expression to

Mazyrski [523]

The expression involving exponents to represent the shaded area in square inches of the diagram is: 6²- (3² + 2²). The shaded area in squares inches of the diagram is: 23 square inches.

<h3>Expression involving exponents and shaded area</h3>

The expression is:

6²- (3² + 2²)

The shaded area:

Shaded area=6²- (3² + 2²)

Shaded area=36-(9+4)

Shaded area=36-13

Shaded area=23 square inches

Therefore the expression involving exponents to represent the shaded area in square inches of the diagram is: 6²- (3² + 2²). The shaded area in squares inches of the diagram is: 23 square inches.

Learn more about Expression involving exponents and shaded area here:brainly.com/question/12529223

brainly.com/question/12560437

#SPJ1

6 0

1 year ago

Which quantities are NOT constant in uniform circular motion? Select all that apply.. . Answer 1. Angular Velocity. 2. Angular p

bagirrra123 [75]

The quantities that are not constant in uniform circular motion are :

1. Angular Velocity , the direction keep changing in angular velocity so it's not constant

2. Angular position, theta will keep on changing until it reach 360

3. Direction of centripetal acceleration

hope this helps

4 0

3 years ago