If we let p and t be the masses of the paper and textbook, respectively, the equations that would best represent the given in this item are:
(1) 20p + 9t = 44.4
(2) (20 + 5)p + (9 + 1)t = 51
The values of p and t from the equation are 0.6 and 3.6, respectively. Thus, each paperback weighs 0.6 pounds and each textbook weighs 3.6 pounds.
Answer:
Step-by-step explanation:
True. The function appears to be f(x) = x/4.
2 miles = 3520 yards
FORMULA multiply the length value by 1760
78 is the significant figure because in maths 0's are not considered significant. Read more into significant figures to help you out.