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AnnyKZ [126]
2 years ago
14

A jar contains jellybeans that are all the same size and shape.

Mathematics
1 answer:
Sergeeva-Olga [200]2 years ago
6 0
G because the first jelly bean was put back so it doesn't matter.
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What's the next number 2 7 8 3 12 9
puteri [66]

The <em>correct answer</em> is:

4.

Explanation:

Taking these numbers as groups of three, we have 2, 7, 8; 3, 12, 9.

In the first group, we can see that we first add 5 and then add 1.

The next group seems to start from the next consecutive number. That is, the first group starts with 2, and the next group starts with 3. The next terms in the second group are found by adding 5 to the second term of the first group (12 = 7+5) and then adding 1 to the third term of the first group (9=8+1); this is because we added 5 and added 1 previously.

Following this pattern, the next group of three would start from the next consecutive number up, 4. The next two terms would be 17 (12+5=17) and 10 (9+1=10).

7 0
3 years ago
Read 2 more answers
If 2m = 4x and 2w = 8x, what is m in terms of w?
Mariana [72]
2^m=2^n  take the natural log of both sides

m*ln2=n*ln2  divide both sides by ln2

m=n
6 0
3 years ago
Read 2 more answers
Solve y ' ' + 4 y = 0 , y ( 0 ) = 2 , y ' ( 0 ) = 2 The resulting oscillation will have Amplitude: Period: If your solution is A
Vlad [161]

Answer:

y(x)=sin(2x)+2cos(2x)

Step-by-step explanation:

y''+4y=0

This is a homogeneous linear equation. So, assume a solution will be proportional to:

e^{\lambda x} \\\\for\hspace{3}some\hspace{3}constant\hspace{3}\lambda

Now, substitute y(x)=e^{\lambda x} into the differential equation:

\frac{d^2}{dx^2} (e^{\lambda x} ) +4e^{\lambda x} =0

Using the characteristic equation:

\lambda ^2 e^{\lambda x} + 4e^{\lambda x} =0

Factor out e^{\lambda x}

e^{\lambda x}(\lambda ^2 +4) =0

Where:

e^{\lambda x} \neq 0\\\\for\hspace{3}any\hspace{3}\lambda

Therefore the zeros must come from the polynomial:

\lambda^2+4 =0

Solving for \lambda:

\lambda =\pm2i

These roots give the next solutions:

y_1(x)=c_1 e^{2ix} \\\\and\\\\y_2(x)=c_2 e^{-2ix}

Where c_1 and c_2 are arbitrary constants. Now, the general solution is the sum of the previous solutions:

y(x)=c_1 e^{2ix} +c_2 e^{-2ix}

Using Euler's identity:

e^{\alpha +i\beta} =e^{\alpha} cos(\beta)+ie^{\alpha} sin(\beta)

y(x)=c_1 (cos(2x)+isin(2x))+c_2(cos(2x)-isin(2x))\\\\Regroup\\\\y(x)=(c_1+c_2)cos(2x) +i(c_1-c_2)sin(2x)\\

Redefine:

i(c_1-c_2)=c_1\\\\c_1+c_2=c_2

Since these are arbitrary constants

y(x)=c_1sin(2x)+c_2cos(2x)

Now, let's find its derivative in order to find c_1 and c_2

y'(x)=2c_1 cos(2x)-2c_2sin(2x)

Evaluating    y(0)=2 :

y(0)=2=c_1sin(0)+c_2cos(0)\\\\2=c_2

Evaluating     y'(0)=2 :

y'(0)=2=2c_1cos(0)-2c_2sin(0)\\\\2=2c_1\\\\c_1=1

Finally, the solution is given by:

y(x)=sin(2x)+2cos(2x)

5 0
3 years ago
In a sample of 5000 flips of a fair coin, tails will always come up 2500 times.
rodikova [14]

true or false? no question?

if so

Faults because 50% is based on each time you flip not the total amount

8 0
3 years ago
How to divide 250 divided by the power of ten
12345 [234]

Answer:

Hello Adam Here!

Step-by-step explanation:

When multiplying by powers of 10, move the decimal point one place to the right for each power of ten. 2. When dividing by powers of 10, move the decimal point one place to the left for each power of ten. The following diagram shows how to multiply and divide numbers by powers of 10.

Hope This Helps From, Adam :)

5 0
2 years ago
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