We have two points:
(-3,5) and (2,-3)
I
An equation in oint-slope form has this shape:
y-y₀=m(x-x₀)
m=slope
1) we compute the slope (m) between two points:
Given two points (x₁,y₁) and (x₂,y₂) the slope between these pointw will be.
m=(y₂-y₁)/(x₂-x₁)
In this case, our slope would be:
m=(-3-5)/(2+3)=-8/5
2) we choose one of these points and replace it in the equation, the result will be the same:
(-3,5)
<span>y-y₀=m(x-x₀)
</span>y-5=-8/5(x+3)
Answer: y-5=-8/5(x+3)
Answer:
6 sec
Step-by-step explanation:
when ball return to the ground, h is 0
0=at^2 +bt
0 = -4.9t^2+29.4t
factor: -4.9 times -6 is 29.4
0 = -4.9t(t-6)
set each equation to 0
-4.9t = 0 or t-6=0
t = 0 or t= 6
it's 6 seconds
Yes most likely a variable square can be combined with a variable I believe
