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Jobisdone [24]
2 years ago
9

Can you please help? I’m tired and I have to work on this

Mathematics
2 answers:
slega [8]2 years ago
6 0
1. 1/3 2. 1/2 3. 4:1 4. 3:4
drek231 [11]2 years ago
3 0

Answer:

1) 1/3

2) 1/2

3) 4/1

4) 3/4

5) 2/5, 4/10, 4:10, 4 to 10

6) 3:4, 6/12, 6:12, 6 to 12

7) 3 to 1, 9/3, 9:3, 9 to 3

8) 7/9, 14/18, 14:18, 14 to 18

9)

a) 3/2

b) 3/5

c) 27:18

10) 96 birds visited the feeder

11)

a) nuts row: 3, 6, 9, 12

   raisins row: 4, 8, 12, 16

b) 7.5 cups

12)

a) This ratio means that for every 9 boys in the school there are 10 girls

b) 570 students

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Brums [2.3K]

Answer:

The original number is (i)

The whole amount is (ii)

Step-by-step explanation:

So when finding a number in a percent you wanna see how much that percent will go into that number. So like if I said how many times does 60% go into 200 you would have to see how many times the number 200 would go into 60%. does this make sense? If so this is how you can find your answer.

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2 years ago
Please help hurry!!!!!!!
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Answer: the answer is 224cm3

6 0
2 years ago
What is the measure of x?<br> x= ✓[?]
Sedbober [7]

Answer:

x=24

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is 6.1% in simplest fraction form?
timama [110]

Answer:

Find the GCD (or HCF) of numerator and denominator. GCD of 6 and 1 is 1.

6 ÷ 11 ÷ 1.

Reduced fraction: 61. Therefore, 6/1 simplified to lowest terms is 6/1.

5 0
2 years ago
Read 2 more answers
In a calculus​ class, Jack Hartig scored 4 on a quiz for which the class mean and standard deviation were 2.9 and 2.1​, respecti
nataly862011 [7]

Answer: Norm Alpina did better with z-score 0.79

Step-by-step explanation:

Z score formula = (raw score - mean) / standard deviation

For Jack Hartig,

score = 4; mean = 2.9; standard deviation = 2.1

Hence, Z score = (4 - 2.9) /2.1

= 1.1/2.1

= 0.52

For Norm Alpina,

score = 8; mean = 6.5; standard deviation = 1.9

Hence, Z score = (8 - 6.5) /1.9

= 1.5/1.9

= 0.79

Relatively, Norm Alpina did better for having Z score 0.79

6 0
3 years ago
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