What is 2y-2x=6 in y=mx+b form

A number is double of another. If the difference of them is 20,Find the Numbers.

Licemer1 [7]

I think the answer is

8 0

3 years ago

Yolanda is planning out her square vegetable garden, One side 6 feet. How

Diano4ka-milaya [45]

Answer:

6^2

Step-by-step explanation:

A square has equal sides. The area of a rectangle or square is LxW. Since the length and width are the same it is squared or put to the power (exponent) of 2.

7 0

3 years ago

3x - 7 - 2x + 5 = 6

IceJOKER [234]

First combine like terms
3x - 7 - 2x + 5 = 6
x - 2 = 6
Get x by itself by adding 2 on both sides
x - 2 = 6
x = 8
Your answer is x = 8

7 0

4 years ago

Read 2 more answers

Please answer this correctly

Mariana [72]

Answer:

50%

Step-by-step explanation:

The numbers that are 2 and even are 2 and 4.

2 numbers out of 4.

2/4 = 1/2

= 0.5

P(2 or even) = 50%

3 0

3 years ago

Match the function in the left column with its period in the right column.

kiruha [24]

The results for the matching between function and its period are:

Option 1 - Letter D
Option 2 - Letter A
Option 3 - Letter C
Option 4 - Letter B

<h3>What is a Period of a Function?</h3>

If a given function presents repetitions, you can define the period as the smallest part of this repetition. As an example of periodic functions, you have: sin(x) and cos(x).

$\mathrm{Period\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}$

$\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}$

The period of sin(x) and cos(x) is 2π.

For solving this question, you should analyze each option to find its period.

1) Option 1

$\mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}\\ \\ \mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{2\pi }{\frac{1}{2} }=4\pi$

Thus, the option 1 matches with the letter D.

2) Option 2

$\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}\\ \\ \mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{4} =\frac{\pi }{2}$

Thus, the option 2 matches with the letter A.

3) Option 3

$\mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\cos \left(x\right)}{|b|}\\ \\ \mathrm{Periodicity\:of\:}a\cdot \cos \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{2} =\pi$

Thus, the option 3 matches with the letter C.

4) Option 4

$\mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{\mathrm{periodicity\:of}\:\sin \left(x\right)}{|b|}\\ \\ \mathrm{Period\:of\:}a\cdot \sin \left(bx\:+\:c\right)\:+\:d=\frac{2\pi}{8} =\frac{\pi }{4}$

Thus, the option 4 matches with the letter B.

Read more about the period of a trigonometric function here:

brainly.com/question/9718162

#SPJ1

6 0

2 years ago