All categories

3 years ago

3x - 7 - 2x + 5 = 6

2 answers:

7 0

First combine like terms
3x - 7 - 2x + 5 = 6
x - 2 = 6
Get x by itself by adding 2 on both sides
x - 2 = 6
x = 8
Your answer is x = 8

Aloiza [94]3 years ago

4 0

Combine like terms!
3x-2x = x
-7+5= -2
x-2=6
get x by itself!
x=8

You might be interested in

Serena has a summer job as a lifeguard at the neighborhood pool. She earns $240 a week. By rounding her weekly income to the nea

Nesterboy [21]

<h2>Answer: B </h2>

Step-by-step explanation:

If your rounding her weekly income you would go down to $200 then take that times 11 for each week, giving you $2,200 roughly

3 0

3 years ago

What value of x makes the equation true?<br><br> 16 + (18 + 10) = (x + 18) + 10<br><br> x = ?

choli [55]

Answer:

See below

Step-by-step explanation:

16 + (18 + 10) = (x + 18) + 10x

16 + 28 = (x + 18) + 10x Add like terms in the parentheses

44 = (x + 10x) + 18 Use the community property to regroup like

terms

44 = 11x + 18 Simply

<u>-18 = -18</u> Substract 18 from both side

26 = 11x Simply

<u>26</u> = <u>11x</u> Divide by 11

11 11

$2\frac{4}{11} = x$ Reduce

3 0

2 years ago

NEED HELP ASAP!!<br> BRAINLEST WILL BE THe PRIZE FOR HELPING

Alina [70]

Answer:

y=2x+2

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

If a family has 6 children, in how many ways could the parents have 3 boys and 3 girls?

Jlenok [28]

The parents could have 3 boys and 3 girls in 400 ways

<h3>How to determine the number of ways?</h3>

The given parameters are

Children, n = 6

Boys, r = 3

Girls, r =3

The number of combination is:

$Ways = ^nC_{r1} *^nC_{r2}$

So, we have:

$Ways = ^6C_3 *^6C_3$

Apply the combination formula

$Ways = \frac{6!}{3!3!} *\frac{6!}{3!3!}$

This gives

Ways = 400

Hence, the parents could have 3 boys and 3 girls in 400 ways

3x - 7 - 2x + 5 = 6​

3x - 7 - 2x + 5 = 6