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3 years ago

Someone Plz help me with this, first to answer will get marked Brainliest

Mathematics

2 answers:

Shtirlitz [24]3 years ago

8 0

To determine the x-intercept, we set y equal to zero and solve for x. Similarly, to determine the y-intercept, we set x equal to zero and solve for y. ...
To find the x-intercept, set y = 0 \displaystyle y=0 y=0.
To find the y-intercept, set x = 0 \displaystyle x=0 x=0.

Hope this helped brainliest is appreciated

kumpel [21]3 years ago

8 0

Answer:

To find the y-intercept, substitute the slope in for m in the formula y = mx + b, and substitute a given ordered pair in the table for x and y in the formula, then solve for b. Finally, substitute the values for m and b into the formula y = mx + b to write the equation of the line.

Step-by-step explanation:

hope this is helpful.

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Rina8888 [55]

Answer:

0.03 more flour per cupcake

Step-by-step explanation:

3.12/8 = 0.39

2.52/7 = 0.36

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3 years ago

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3 years ago

find 2 consecutive integers such that three times the square of the first is equal to seven more than five times the second

melamori03 [73]

Answer:

Step-by-step explanation:

We are looking for two numbers, $N$ and $N + 1$ . From the problem statement, we can setup the following equation:

$3N^{2} = 5(N + 1) + 7$

$3N^{2} = 5N + 5 + 7$

$3N^{2} - 5N - 12 = 0$

$(3N + 4)(N - 3)$

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Because 3 is the only integer solution, the answer is 3 and 4.

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3 years ago

HELP ASAP!!!! Does someone mind walking me through this. I really need help.

Tamiku [17]

The minimum of this graph is the focus of the parabola. I'm not sure with the maximum though but I think it doesn't have a maximum because the y value of the parabola will extend infinitely upward.

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3 years ago

A batch consists of 12 defective coils and 88 good ones. Find the probability of getting two good coils when two coils are rando

Allushta [10]

Answer:

The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744

Solution:

Total number of coils = number of good coils + defective coils = 88 + 12 = 100

p(getting two good coils for two selection) = p( getting 2 good coils for first selection ) $\times$ p(getting 2 good coils for second selection)

p(first selection) = p(second selection) = $\frac{\text { number of good coils }}{\text { total number of coils }}$

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3 years ago