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VMariaS [17]
2 years ago
8

Jasmine is painting a rectangular wall in her bedroom that has a base of 12 feet and a height of 8 feet. There is a square windo

w on the wall with a side length of 3 feet. She has enough paint to cover 90 square feet. Does she have enough paint? Explain your reasoning.
Mathematics
1 answer:
bija089 [108]2 years ago
6 0

Answer:

The answer to your question is Yes, she has enough paint.

Step-by-step explanation:

Data

base = 12 ft

height = 8 ft

window = 3 ft x 3 ft

Process

1.- Calculate the area of the wall

Area = base x height

Area = 12 x 8

Area = 96 ft²

2.- Calculate the are of the wall

Area = side x side

Area = 3 x 3

Area = 9 ft²

3.- Calculate the area that need to be painted

Area painted = Area of the wall - Area of the window

-Substitution

Area painted = 96 - 9

                      = 87 ft²

4.- Conclusion

She has enough paint to paint the wall (90 ft² > 87 ft²).

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Take it step by step.

The area of a rectangle is width times length.

We know the length is 7 since it's given, and we can find the width by adding shared sides of the square and triangle.

So the width is 10 + 14 or 24

That means the area of the rectangle is 7 * 24

The area of the second rectangle is 12 * 14, since they are both given.

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3 0
3 years ago
An engineer stands 200 feet from a tower and sights the top of the tower at a 45° angle of elevation. Find the height of the tow
Alik [6]
Drawing a diagram of a triangle may be helpful. The hypotenuse is irrelevant, but the vertical leg and the horizontal leg are useful. Since we know the engineer is looking up at a 45 degree angle from a distance of 200 feet, we can label the vertical leg the "opposite", since it is on the opposite side of the angle we are given. The horizontal leg then becomes the "adjacent". You can then use trigonometry to solve for the opposite. 
The options are:
sin(theta)= opposite/hypotenuse
cos(theta)= adjacent/hypotenuse
tan(theta)= opposite/adjacent
Since we don't care about the hypotenuse, the last equation is the one to use. The angle we are given can be substituted in for theta:
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