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3 years ago

A function is represented by the values in the table.

Mathematics

2 answers:

AleksAgata [21]3 years ago

8 0

Answer:

its possibly the third its the only one diffrent from the others

Step-by-step explanation:

lana [24]3 years ago

5 0

The answer is a its linear i think

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In a factory, the chance that a certain machine works without overheating in the morning is 50%. if it runs smoothly all morning

Degger [83]

Answer: C. 7.5%

Solve as decimal

0.5*0.15=0.075

Move two decimal points over

0.075 -> 7.5

Change back to percent

7.5%

3 0

2 years ago

Find the value of the variable in the parallelogram. RZ = 4x + 2 SW=9x - 8 X=

ipn [44]

Answer:

$x=12$

Step-by-step explanation:

This parallelogram contains a right angle. This tells us that the parallelogram is a rectangle.

The diagonals in a parralelogram bisect each other.

The diagonals in a rectangle are congruent.

$RZ+ZT=RT\\(4x+2)+(4x+2)=RT\\8x+4=RT$

$RT=SW\\8x+4=9x-8\\4=x-8\\x=12$

8 0

3 years ago

5 × -92 = Just a quick response on how to solve this, thanks a ton!

Colt1911 [192]

Answer:

-460

Step-by-step explanation:

I multiply by splitting the numbers into digits. So for the 90, in my head I did 5 × 90, which is 450. Then I did 2 × 5, this is 10. Now I added those up to make 460. Considering the 92 is negative, the answer will also be negative.

8 0

4 years ago

Read 2 more answers

Who can help me d e f thanks

12345 [234]

$y = (2ax^2 + c)^2 (bx^2 - cx)^{-1}$

Product rule:

$y' = \bigg((2ax^2+c)^2\bigg)' (bx^2-cx)^{-1} + (2ax^2+c)^2 \bigg((bx^2-cx)^{-1}\bigg)'$

Chain and power rules:

$y' = 2(2ax^2+c)\bigg(2ax^2+c\bigg)' (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} \bigg(bx^2-cx\bigg)'$

Power rule:

$y' = 2(2ax^2+c)(4ax) (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} (2bx - c)$

Now simplify.

$y' = \dfrac{8ax (2ax^2+c)}{bx^2 - cx} - \dfrac{(2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}$

$y' = \dfrac{8ax (2ax^2+c) (bx^2 - cx) - (2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}$

$y = \dfrac{3bx + ac}{\sqrt{ax}}$

Quotient rule:

$y' = \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{\left(\sqrt{ax}\right)^2}$

$y'= \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{ax}$

Power rule:

$y' = \dfrac{3b \sqrt{ax} - (3bx+ac) \left(-\frac12 \sqrt a \, x^{-1/2}\right)}{ax}$

Now simplify.

$y' = \dfrac{3b \sqrt a \, x^{1/2} + \frac{\sqrt a}2 (3bx+ac) x^{-1/2}}{ax}$

$y' = \dfrac{6bx + 3bx+ac}{2\sqrt a\, x^{3/2}}$

$y' = \dfrac{9bx+ac}{2\sqrt a\, x^{3/2}}$

$y = \sin^2(ax+b)$

Chain rule:

$y' = 2 \sin(ax+b) \bigg(\sin(ax+b)\bigg)'$

$y' = 2 \sin(ax+b) \cos(ax+b) \bigg(ax+b\bigg)'$

$y' = 2a \sin(ax+b) \cos(ax+b)$

We can further simplify this to

$y' = a \sin(2(ax+b))$

using the double angle identity for sine.

7 0

2 years ago

A cylindrical pipe is 25 ft long and has a volume of 900ft3 find it's approximate diameter to the nearest hundredth of a foot

Andrew [12]

Answer:

Diameter of the pipe ≈ 6.77 ft

Step-by-step explanation:

Volume of a cylinder = πr²h

Here, r = Radius of the cylindrical pipe

h = Length of the pipe

Volume of the pipe = 900 ft³

Length of the pipe = 25 ft

By substituting the given values in the formula,

900 = π(r)²(25)

r² = $\frac{900}{25\pi}$

r = √11.459

r = 3.385

Diameter = 2(radius)

= 2(3.385)

= 6.77 ft

3 0

3 years ago