Using the form y=a(x-h)²+k
We can look at the vertex (-3,-2) which gives us the values of h,k
h=3, k=-2
Thus y=a(x+3)²-2
Then we can solve for a using any point on the line
- I'll use (-4,-1)
Insert the values of x,y into y=a(x+3)²-2
--> x=-4, y=-1
y=a(x+3)²-2
-1=a(-4+3)²-2
-1=a(-1)²-2
a-2=-1
a=-1+2
a=1
Insert the value of a
y=1(x+3)²-2
= (x+3)²-2
Thus y=(x+3)²-2 is the final equation in standard form
Hope this helps :) with your problem
All angles in a triangle add up to 180 degrees.
We are finding the value for both y's (they are congruent) so I'll just plug in the answers to the problem.
Let's start with 54.
54*2=108
108+72=180
The answer is then A, 54 degrees
