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MariettaO [177]
4 years ago
8

Sec theta is undefined for theta=?

Mathematics
1 answer:
aksik [14]4 years ago
8 0
It would have to be ofr gamma perhaps?
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10/27 (3/8 divided by 5/24
GuDViN [60]

Answer:

2/3 is the answer. You could also put 0.6, which is the decimal form of 2/3

I hope this helps you!Step-by-step explanation:

8 0
2 years ago
The the seats in the van are in pairs there are 16 seats How many pairs of seats are there
miskamm [114]
Eight, I am pretty sure. Eight times two is 16.
4 0
3 years ago
Read 2 more answers
Please help. How do you find cosine, sine, cosecant and secant with this triangle? ​
Veseljchak [2.6K]

Hi there! You have to remember these 6 basic Trigonometric Ratios which are:

  • sine (sin) = opposite/hypotenuse
  • cosine (cos) = adjacent/hypotenuse
  • tangent (tan) = opposite/adjacent
  • cosecant (cosec/csc) = hypotenuse/opposite
  • secant (sec) = hypotenuse/adjacent
  • cotangent (cot) = adjacent/opposite
  • cosecant is the reciprocal of sine
  • secant is the reciprocal of cosine
  • cotangent is the reciprocal of tangent

Back to the question. Assuming that the question asks you to find the cosine, sine, cosecant and secant of angle theta.

What we have now are:

  • Trigonometric Ratio
  • Adjacent = 12
  • Opposite = 10

Looks like we are missing the hypotenuse. Do you remember the Pythagorean Theorem? Recall it!

  • a²+b² = c²

Define that c-term is the hypotenuse. a-term and b-term can be defined as adjacent or opposite

Since we know the value of adjacent and opposite, we can use the formula to find the hypotenuse.

  • 10²+12² = c²
  • 100+144 = c²
  • 244 = c²

Thus, the hypotenuse is:

\large \boxed{c = 2 \sqrt{61} }

Now that we know all lengths of the triangle, we can find the ratio. Recall Trigonometric Ratio above! Therefore, the answers are:

  • cosine (cosθ) = adjacent/hypotenuse = 12/(2√61) = 6/√61 = <u>(6√61) / 61</u>
  • sine (sinθ) = opposite/hypotenuse = 10/(2√61) = 5/√61 = <u>(5√61) / 61</u>
  • cosecant (cscθ) is reciprocal of sine (sinθ). Hence, cscθ = (2√61/10) = <u>√61/5</u>
  • secant (secθ) is reciprocal of cosine (cosθ). Hence, secθ = (2√61)/12 = <u>√</u><u>61</u><u>/</u><u>6</u>

Questions can be asked through comment.

Furthermore, we can use Trigonometric Identity to find the hypotenuse instead of Pythagorean Theorem.

Hope this helps, and Happy Learning! :)

5 0
3 years ago
Solve the following expression when<br> t = 3 and s = 2<br> (12t) = (6s)<br> Enter
larisa86 [58]

From the solution of the expression, it can be seen that s = 6 when t = 3 while t = 1 when s = 2.

<h3>How do we solve a mathematical expression?</h3>

Given:

(12t) = (6s) ........................ (1)

When t = 3, we can solve for s from the expression in equation (1) by substituting t = 3 into the equation as follows:

12 * 3 = 6s

36 = 6s

s = 36 / 6

s = 6

When s = 2, we can solve for t from the expression in equation (1) by substituting s = 2 into the equation as follows:

12t = 6 * 2

12t = 12

t = 12 / 12

t = 1

Learn more about mathematical expression here: brainly.com/question/12401681.

#SPJ1

7 0
2 years ago
A device produces random 64-bit integers at a rate of one billion per second. After how many years of running is it unavoidable
nikitadnepr [17]

Answer:

3171 × 10^(44) years

Step-by-step explanation:

For each bit, since we are looking how many years of running it is unavoidable that the device produces an output for the second time, the possible integers are from 0 to 9. This is 10 possible integers for each bit.

Thus, total number of possible 64 bit integers = 10^(64) integers

Now, we are told that the device produces random integers at a rate of one billion per second (10^(9) billion per second)

Let's calculate how many it can produce in a year.

1 year = 365 × 24 × 60 × 60 seconds = 31,536,000 seconds

Thus, per year it will produce;

(10^(9) billion per second) × 31,536,000 seconds = 3.1536 × 10^(16)

Thus;

Number of years of running is it unavoidable that the device produces an output for the second time is;

(10^(64))/(3.1536 × 10^(16)) = 3171 × 10^(44) years

6 0
3 years ago
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