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3 years ago

EVALUATE THE FUNCTION: g(8) Let g(x) = x2 + 4x − 1.

1 answer:

8 0

1. Let g(x) = x2 ... d. f(4). 74. 4. 34. 3. Let g(x) = x2 + 4x - 1. Find the following: a. g(-4) b. g(8) c. g(-1) d. g(1).

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Answer the following questions about 2 numbers chosen from the numbers 1 through 12 (including 1 and 12): Suppose the numbers ar

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2 years ago

If Lauren can jog 2 miles in 2/5 hours, she can jog _____ miles in 1 hour.

kenny6666 [7]

Answer:

1/5 miles

Step-by-step explanation:

2/5 divided by 2 = 1/5

5 0

2 years ago

Can someone help me with this? I’ll mark you brainliest

nirvana33 [79]

Answer:

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8 0

2 years ago

Shortern this expression pls

pogonyaev

Answer:

$c =\frac{8}{3}$

Step-by-step explanation:

Given

$c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}$

Required

Shorten

We have:

$c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}$

Rationalize

$c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7} * \frac{4 + \sqrt 7}{4 + \sqrt 7}} + \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}*\frac{4 - \sqrt 7}{4 - \sqrt 7}}$

Expand

$c = \sqrt{\frac{(4 + \sqrt 7)^2}{4^2 - (\sqrt 7)^2}} + \sqrt{\frac{(4 - \sqrt 7)^2}{4^2 - (\sqrt 7)^2}$

$c = \sqrt{\frac{(4 + \sqrt 7)^2}{16 - 7}} + \sqrt{\frac{(4 - \sqrt 7)^2}{16 - 7}$

$c = \sqrt{\frac{(4 + \sqrt 7)^2}{9}} + \sqrt{\frac{(4 - \sqrt 7)^2}{9}$

Take positive square roots

$c =\frac{4 + \sqrt 7}{3} + \frac{4 - \sqrt 7}{3}$

Take LCM

$c =\frac{4 + \sqrt 7 + 4 - \sqrt 7}{3}$

Collect like terms

$c =\frac{4 + 4+ \sqrt 7 - \sqrt 7}{3}$

$c =\frac{8}{3}$

4 0

3 years ago

Inequality 2x > x + 7 is equivalent to ?

Pavel [41]

Answer:

x>7

Step-by-step explanation:

We do 2 steps

2x > x + 7

that means

2x - x > x - x + 7

then

x > 7

That is the answer. Hope it useful for you!

4 0

3 years ago