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vampirchik [111]
3 years ago
11

EVALUATE THE FUNCTION: g(8) Let g(x) = x2 + 4x − 1.

Mathematics
1 answer:
Alja [10]3 years ago
8 0
1. Let g(x) = x2 ... d. f(4). 74. 4. 34. 3. Let g(x) = x2 + 4x - 1. Find the following: a. g(-4) b. g(8) c. g(-1) d. g(1).
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Answer the following questions about 2 numbers chosen from the numbers 1 through 12 (including 1 and 12): Suppose the numbers ar
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2 years ago
If Lauren can jog 2 miles in 2/5 hours, she can jog _____ miles in 1 hour.
kenny6666 [7]

Answer:

1/5 miles

Step-by-step explanation:

2/5 divided by 2 = 1/5

5 0
2 years ago
Can someone help me with this? I’ll mark you brainliest
nirvana33 [79]

Answer:

sorry man can't help you with this one

8 0
2 years ago
Shortern this expression pls​
pogonyaev

Answer:

c =\frac{8}{3}

Step-by-step explanation:

Given

c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} +  \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}

Required

Shorten

We have:

c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} +  \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}

Rationalize

c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7} * \frac{4 + \sqrt 7}{4 + \sqrt 7}} +  \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}*\frac{4 - \sqrt 7}{4 - \sqrt 7}}

Expand

c = \sqrt{\frac{(4 + \sqrt 7)^2}{4^2 - (\sqrt 7)^2}} +  \sqrt{\frac{(4 - \sqrt 7)^2}{4^2 - (\sqrt 7)^2}

c = \sqrt{\frac{(4 + \sqrt 7)^2}{16 - 7}} +  \sqrt{\frac{(4 - \sqrt 7)^2}{16 - 7}

c = \sqrt{\frac{(4 + \sqrt 7)^2}{9}} +  \sqrt{\frac{(4 - \sqrt 7)^2}{9}

Take positive square roots

c =\frac{4 + \sqrt 7}{3} +  \frac{4 - \sqrt 7}{3}

Take LCM

c =\frac{4 + \sqrt 7 + 4 - \sqrt 7}{3}

Collect like terms

c =\frac{4  + 4+ \sqrt 7 - \sqrt 7}{3}

c =\frac{8}{3}

4 0
3 years ago
Inequality 2x > x + 7 is equivalent to ?
Pavel [41]

Answer:

x>7

Step-by-step explanation:

We do 2 steps

2x > x + 7

that means

2x - x > x - x + 7

then

x > 7

That is the answer. Hope it useful for you!

4 0
3 years ago
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