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insens350 [35]
4 years ago
12

NEED HELP 6-10 PLS ASAP WILL MARK BRAINLIEST

Mathematics
1 answer:
hichkok12 [17]4 years ago
8 0

Answer:

6: False

7: False

8: True

9: True

10: False

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Pls help due today I will Give crown
bezimeni [28]

Answer: C

Step-by-step explanation:

Crown?

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3 years ago
Write the equation of a line passing through the points (5,-5) and (-5,-5)?
zmey [24]

Answer:

y-(-5)/x-(-5)=0

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Which graph shows a system of equations with no solutions? On a coordinate plane, the graphs of 2 circles are shown. Both circle
daser333 [38]

Answer:

1st Graph: 2 circles are shown

Step-by-step explanation:

In order to have a solution set, the 2 graphs need to intersect each other. All the graphs but the 2 circles intersect and have a solution. Therefore, our answer is the 1st Graph.

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Which of the following is a solution to this inequality?
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Step-by-step explanation:

5 0
3 years ago
Consider the function V=g(x), where g(x) =x(6-2x)(8-2x), with x being the length of a cutout in cm and V being the volume of an
Andrej [43]

Answer:

The maximum volume of the open box is 24.26 cm³

Step-by-step explanation:

The volume of the box is given as V=g(x), where g(x)=x(6-2x)(8-2x) and 0\le x\le3.

Expand the function to obtain:

g(x)=4x^3-28x^2+48x

Differentiate  wrt  x to obtain:

g'(x)=12x^2-56x+48

To find the point where the maximum value occurs, we solve

g'(x)=0

\implies 12x^2-56x+48=0

\implies x=1.13,x=3.54

Discard x=3.54 because it is not within the given domain.

Apply the second derivative test to confirm the maximum critical point.

g''(x)=24x-56, g''(1.13)=24(1.13)-56=-28.88\:

This means the maximum volume occurs at x=1.13.

Substitute x=1.13 into g(x)=x(6-2x)(8-2x) to get the maximum volume.

g(1.13)=1.13(6-2\times1.13)(8-2\times1.13)=24.26

The maximum volume of the open box is 24.26 cm³

See attachment for graph.

6 0
4 years ago
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