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3 years ago

Help me i will give brainliest...Have a goodnight

Mathematics

1 answer:

DerKrebs [107]3 years ago

6 0

Answer:

apparently 6 sq in.

Step-by-step explanation:

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What is the volume of the square pyramid with base edges 18 m and slant height 15 m

vlada-n [284]

check the picture below.

so it has a base of 18x18 and a height of that much.

$\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh~~ \begin{cases} B=area~of\\ \qquad its~base\\ h=height\\ ------\\ B=\stackrel{18\times 18}{324}\\ h=12 \end{cases}\implies V=\cfrac{1}{3}(324)(12)\implies V=1296$

8 0

3 years ago

Read 2 more answers

When you find the surface area of a cube, you ________ the length of the cube and multiply by 6.

garik1379 [7]

Answer:

A-square

Step-by-step explanation:

The formula for the surface area of a cube is:

SA = 6a²

where a is the length of the cube

7 0

3 years ago

The relationship between the amount of data downloaded d, in megabytes, and the time t, in seconds, after the download started i

svetoff [14.1K]

Answer: A, C, F, there’s 4 but I only know 3

6 0

3 years ago

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student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$

= $(\frac{1}{4})^3\times (\frac{3}{4})^2+(\frac{1}{4})^4\times (\frac{3}{4})+(\frac{1}{4})^5$

= $(\frac{1}{4})^3\times (\frac{3}{4})[\frac{3}{4}+\frac{1}{4}+(\frac{1}{4})^2]$

= $(\frac{3}{4^4})[1+\frac{1}{16}]$

= $(\frac{3}{256})[\frac{17}{16}]$

= 0.01171875 × 1.0625

= 0.01245

Thus, the probability that at least 3 out of 5 students receive version A is 0.0124

So, in percent the probability is 0.0124 × 100 = 1.24%

To the nearest tenth, the required probability is 1.2%.

4 0

3 years ago

Find the area of the figure. Round to the nearest tenth

Reika [66]

Answer:

Find the area of each triangle and then add it up. As you are aware, to find the area of a triangle the equation is B times Height divided by 2. And to make it easier do the top left triangle and the top right triangle, add them together and then divide that by 2.

Step-by-step explanation:

3 time 5 equals 15 divided by 2 equals 7.5

5 times 8 equals 40 divided by 2 equals 20

7.5 plus 20 equals 27.5

27.5 times 2 equals 55

therefor your answer should be 55m

3 0

2 years ago