20 + 12 + x = 48 / -20
12 + X = 48 - 20 / -12
X = 48 - 20 - 12
X = 28 - 12
X = 16
Answer:
See attachment
Step-by-step explanation:
Given
![Side\ 1 = 10cm](https://tex.z-dn.net/?f=Side%5C%201%20%3D%2010cm)
![Side\ 2 = 12cm](https://tex.z-dn.net/?f=Side%5C%202%20%3D%2012cm)
![\theta = 90^\circ](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2090%5E%5Ccirc)
Required [Missing from the question]
Draw the top of the cake
See attachment for reference.
From the attachment,
![2cm = 1\ unit](https://tex.z-dn.net/?f=2cm%20%3D%201%5C%20unit)
So:
![Side\ 1 = 10cm](https://tex.z-dn.net/?f=Side%5C%201%20%3D%2010cm)
![Side\ 1 = 5 * 2cm](https://tex.z-dn.net/?f=Side%5C%201%20%3D%205%20%2A%202cm)
Substitute ![2cm = 1\ unit](https://tex.z-dn.net/?f=2cm%20%3D%201%5C%20unit)
![Side\ 1 = 5 * 1unit](https://tex.z-dn.net/?f=Side%5C%201%20%3D%205%20%2A%201unit)
![Side\ 1 = 5\ units](https://tex.z-dn.net/?f=Side%5C%201%20%3D%205%5C%20units)
![Side\ 2 = 12cm](https://tex.z-dn.net/?f=Side%5C%202%20%3D%2012cm)
![Side\ 2 = 6 * 2cm](https://tex.z-dn.net/?f=Side%5C%202%20%3D%206%20%2A%202cm)
Substitute ![2cm = 1\ unit](https://tex.z-dn.net/?f=2cm%20%3D%201%5C%20unit)
![Side\ 2 = 6 * 1unit](https://tex.z-dn.net/?f=Side%5C%202%20%3D%206%20%2A%201unit)
![Side\ 2 = 6\ units](https://tex.z-dn.net/?f=Side%5C%202%20%3D%206%5C%20units)
This means that, the given side lengths will be represented by 5 units and 6 units on the grid, respectively.
<em>See attachment for drawing</em>
Answer:
<h3>
<em>a</em><em>.</em><em> </em><em> </em><em>1</em><em>1</em></h3><h3>
<em>b</em><em>.</em><em> </em><em> </em><em>9</em></h3>
<em>Sol</em><em>ution</em><em>,</em>
<em>a</em><em>.</em><em> </em><em> </em><em> </em><em>Given</em><em>,</em>
<em>X=</em><em>4</em>
<em>y</em><em>=</em><em>3</em>
<em>Now</em><em>,</em>
<em>
</em>
<em>b</em><em>.</em><em> </em><em>Given,</em>
<em>a</em><em>=</em><em>-</em><em>2</em>
<em>b</em><em>=</em><em>5</em>
<em>Now</em><em>,</em>
<em>
</em>
<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>