Answer:
(x+5)^2+(y-12)^2=256
Step-by-step explanation:
Comparing the given (x+5)^2+(y-12)^2=256
to (x - h)^2 + (y - k)^2 = r^2,
we see that h must be -5, k must be 12 and r must be 16. This is the desired equation of the circle with center at (-5, 12) and radius 16.
I found width=13.72 ft and length=43.72 ft.
Call one dimension of the rectangle x, the other will be x+30
You want an area A=600 ft^2 but A=length x width=x*(x+30)=600
Rearranging you get:

solving this quadratic equation you get a negative solution and a positive one that gives your result.
The factors are 6 and x + 5
You have not provided the figures, therefore, I cannot provide an exact answer.
However, I can helps you with the steps.
One important thing to note is that when writing statements of congruency, the order of writing the letters is very important. This is because each side/angle in the first figure would be congruent to the corresponding side/angle in the second.
Therefore, all you have to do in the above question is write the congruent figures and determine the corresponding congruent sides/angles
Example:
If we are given that triangle ABC is congruent to triangle DEF
This means that:
AB = DE
BC = EF
AC = DF
angle A = angle D
angle B = angle E
angle C = angle F
Hope this helps :)
Answer:
a) Average velocity at 0.1 s is 696 ft/s.
b) Average velocity at 0.01 s is 7536 ft/s.
c) Average velocity at 0.001 s is 75936 ft/s.
Step-by-step explanation:
Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by
.
To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s.
, b. 0.01 s.
, c. 0.001 s.
Solution :
a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.





b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.





c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.



