First, I would distribute the 2 out to the (x+4).
2x+8.
Next, use the foil method to multiply together 2x+8 and (x+3).
2x^2 +14x+24.
Do the same process for the other side.
3(x+2)= 3x+6
(3x+6)(x-1)= 3x^2+3x-6
Set the remaining products of each side of the equation equal to each other.
2x^2 +14x+24=3x^2+3x-6.
Now you must cancel out one side to make the equation equal to zero. Do this by doing the inverse operation on one side of the equation (each value with their like term). I am going to subtract the left side values from the right:
This means:
3x^2 minus 2x^2 equals 1x^2 (or just x^2).
3x minus 14x equals -11x
-6 minus 24 equals -30
The equation should now look like this:
0=x^2-11x-30
Reverse the order to get zero on the right side:
x^2-11x-30=0
Hope this helps! Sorry if I made any careless mistakes (^^;)
Answer:
a c e
Step-by-step explanation:
just did it
Assuming your system of equations is
The answer is C. Infinitely many solutions. If my assumption is incorrect, then the answer will be likely different.
The reason why it's "infinitely many solutions" is because the first equation is the same as the second equation. The only difference is that everything was multiplied by -1. You could say that both sides were multiplied by -1.
Both equations given graph out the same line. They overlap perfectly yielding infinitely many solution points on the line.
Answer:
Step-by-step explanation:
I think that X = -2 and Y = 1
I hope my answer will serve you.
