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3 years ago

I need help! Please answer before 4:00 pm today! Thank you so much!

Mathematics

1 answer:

QveST [7]3 years ago

4 0

Answer=0 because 7,8 because 7 times 8 = 56 and 56-56 = 0

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3. Escribe la ecuación de la elipse que cumple con:<br> F1(-3,0) F2(3,0) y a=4

maks197457 [2]

Answer:

Step-by-step explanation:

7 0

3 years ago

Expand -8 to the 3rd power

BigorU [14]

Use a calculator lollll

8 0

3 years ago

Two column proofs Beginner's

Darina [25.2K]

LETS prove the 2nd part of the Question

Here concept of right angles is used

We can see BA is perp to BD

and BC is perp to BE

We have to prove angle 1 = angle 3

i will denote angle by a

therefore we need to prove a1 = a3

as BA is perp to BD hence angle between them will be 90 degree

a1 + a2 = 90 degree

Similarly BC is perp to BE

a2 + a3 = 90 degree

as both equations add up gives 90 degree so will equate them

a1 + a2 = a2 + a3

which means a1 = a3

Hence Proved

To learn more about Right Angles:

brainly.com/question/7116550

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3 0

1 year ago

Look at the diagram. Which of the following is another name ∠2?

____ [38]

The other name for angle 2 is ∠DBC

The correct option is (D)

<h3>What is Angle?</h3>

A figure which is formed by two rays or lines that shares a common endpoint is called an angle.

We know that while naming the angle we have to consider the point where the angle is made should be at center.

Hence, the angle 2 can also be written as ∠DCB.

Learn more about angle here:

brainly.com/question/13954458

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8 0

2 years ago

You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o

Aleksandr [31]

Answer:

Therefore the circumference of the circle is $=\frac{20\pi}{4+\pi}$

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

$\Rightarrow s=\frac{10-\pi r}{2}$

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

$A=\pi r^2+ (\frac{10-\pi r}{2})^2$

$\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2$

$\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}$

$\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25$

For maximum or minimum $\frac{dA}{dr}=0$

Differentiating with respect to r

$\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi$

Again differentiating with respect to r

$\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}$ > 0

For maximum or minimum

$\frac{dA}{dr}=0$

$\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0$

$\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}$

$\Rightarrow r=\frac{10}{4+\pi}$

$\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0$

Therefore at $r=\frac{10}{4+\pi}$ , A is minimum.

Therefore the circumference of the circle is

$=2 \pi \frac{10}{4+\pi}$

$=\frac{20\pi}{4+\pi}$

4 0

3 years ago