Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides).  If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.
Let's see whether they do.
8^2 + 8^2 = 11^2  ???
 64    + 64 = 121?  NO.  This is not a right triangle.
If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:
8^2 + 8^2 = d^2, where d=hypotenuse.  Then 64+64 = d^2, and 
d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.
11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.
        
             
        
        
        
This question is asking "Where does cosine equal 

?"
Based on our unit circle values and the domain of the cos^{-1} function, we see that at 30 degrees, or 

, cosine is equal to 

.
 
        
        
        
1/2 is the simpliest form,divide everything by 2
        
                    
             
        
        
        
Answer:
x = 48
Step-by-step explanation:

 
        
                    
             
        
        
        
3 pound og tomatoes can fit into one crate o believe