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Margarita [4]
3 years ago
12

Find the product of (2x + 5y)(2x − 5y).

Mathematics
2 answers:
Nana76 [90]3 years ago
7 0
The final answer for this is 4x^2-25y^2.
Whitepunk [10]3 years ago
4 0

Answer:

Option D  is correct.

the product of (2x+5y)(2x-5y) is, 4x^2-25y^2

Step-by-step explanation:

Using identity rule:

(a+b)(a-b) = a^2-b^2

To find the product of:

(2x+5y)(2x-5y)

Apply the identity rule:

here, a = 2x and b = 5y then

(2x+5y)(2x-5y) =(2x)^2-(5y)^2

=4x^2-25y^2

Therefore, the product of (2x+5y)(2x-5y) is, 4x^2-25y^2

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A personnel director at a large company studied the eating habits of employees by watching the movements of a selected group of
Gnesinka [82]

Answer:

  1. c) an observational study
  2. c) convenience sample
  3. a) blocking for gender

Step-by-step explanation:

It is an abservational study because she is only watching and not asking the all or a group of employees to tell her their response to what she wants to know.

It is a convenience sample because subjects are selected because of their closeness to the researcher.

8 0
3 years ago
Graph the circle x^2+y^2+2x+4y-44=0
Natasha_Volkova [10]

Answer:

See explanation

Step-by-step explanation:

First, convert this to standard form. By completing the square, you can do the following:

(x^2+2x+1)-1+(y^2+4y+4)-4-44=0

(x+1)^2+(y+2)^2=49

This is a circle with center (-1,-2), and radius 7. It looks like the one I graphed below. Hope this helps!

6 0
3 years ago
1 Factor completely.
bulgar [2K]

1 Factor completely.

p2+7p+10 = (p + 5)(p + 2)



 2 Factor completely.

x2+10x+16 = (x + 4)(x + 6)


3 Factor completely.

x2+7x−18 = (x + 9)(x - 2)



 4 Factor completely.

x2−5x−24 = (x - 8)(x + 3)



 5 Factor completely.

x2−3x−40 = (x - 8)(x + 5)

6 0
3 years ago
Read 2 more answers
Stan worked 4 years less than Marco. This year Stan has worked 29 years. If b is how long Marco worked, the equation b – 4 = 29
My name is Ann [436]
By adding 4 to both side
7 0
3 years ago
Read 2 more answers
Find the volume of the composite figure​
AURORKA [14]

39in³ is a required volume.

Solution given:

for upper one

length[l]=8in

breadth[b] =3in

height[h]=1in

now

volume [V1]=l×b×h=8×3×1=24in³

again for lower one:

length[l]=6-1=5in

breadth[b] =3in

height[h]=1in

volume [V2]=l×b×h=5×3×1=15in³

Again

total volume =V1+V2=24in³+15in³=39in³

6 0
3 years ago
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