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3 years ago

Find the product of (2x + 5y)(2x − 5y).

Mathematics

2 answers:

Nana76 [90]3 years ago

7 0

The final answer for this is 4x^2-25y^2.

Whitepunk [10]3 years ago

4 0

Answer:

Option D is correct.

the product of $(2x+5y)(2x-5y)$ is, $4x^2-25y^2$

Step-by-step explanation:

Using identity rule:

$(a+b)(a-b) = a^2-b^2$

To find the product of:

$(2x+5y)(2x-5y)$

Apply the identity rule:

here, a = 2x and b = 5y then

$(2x+5y)(2x-5y) =(2x)^2-(5y)^2$

= $4x^2-25y^2$

Therefore, the product of $(2x+5y)(2x-5y)$ is, $4x^2-25y^2$

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The properties of the mathematical sequence allow us to find that the recurrence term is 1 and the operation for each sequence is

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b) Addition

c) AdditionSum

d) in this case we have two possibilities

* If we move to the right the addition

* If we move to the left the subtraction

The sequence is a set of elements arranged one after another related by some mathematical relationship. The elements of the sequence are called terms.

The sequences shown can be defined by recurrence relations.

Let's analyze each sequence shown, the ellipsis indicates where the sequence advances.

a) ... -7, -6, -5, -4, -3

We can observe that each term has a difference of one unit; if we subtract 1 from the term to the right, we obtain the following term

-3 -1 = -4

-4 -1 = -5

-7 -1 = -8

Therefore the mathematical operation is the subtraction.

b) $0. \sqrt{1}. \sqrt{4}, \sqrt{9}, \sqrt{16}, \sqrt{25}$ ...

In this case we can see more clearly the sequence when writing in this way

$0, \sqrt{1^2}. \sqrt{2^2}, \sqrt{3^2 } . \sqrt{4^2} , \sqrt{5^2}$

each term is found by adding 1 to the current term,

$\sqrt{(0+1)^2} = \sqrt{1^2} \\\sqrt{(1+1)^2} = \sqrt{2^2}\\\sqrt{(2+1)^2} = \sqrt{3^2}\\\sqrt{(5+1)^2} = \sqrt{6^2}$

Therefore the mathematical operation is the addition

c) $... \frac{-10}{2}. \frac{-8}{2}, \frac{-6}{2}, \frac{-4}{2}. \frac{-2}{2}. ...$

The recurrence term is unity, with the fact that the sequence extends to the right and to the left the operation is

To move to the right add 1

- $\frac{-10}{2} + 1 = \frac{-10}{2} - \frac{2}{2} = \frac{-8}{2}\\\frac{-8}{2} + \frac{2}{2} = \frac{-6}{2}$

To move left subtract 1

$\frac{-2}{2} - 1 = \frac{-4}{2}\\\frac{-4}{2} - \frac{2}{2} = \frac{-6}{2}$

Using the properties the mathematical sequence we find that the recurrence term is 1 and the operation for each sequence is

a) Subtraction

b) Sum

c) Sum

d) This case we have two possibilities

If we move to the right the sum

If we move to the left we subtract

Learn more here: brainly.com/question/4626313

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Next, you should combine your like terms. So, -14.76 = -88.56.

Then, divide both sides of the equation by the coefficient of variable. So, x = -88.56 / -14.76./

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