The probability that the train will be there when Alex arrives is 5/18
If Alex arrives at any time after 1.20pm the chances that train will be there is 1/3.
However if alex arrives at 1.00pm exactly there is no chance the train will be arrive there.
The probability that the train will be there increase linearly to 1/3 as alex's arrival time moves from 1.00pm to 1.20pm.
By arranging the probabilities over the first 20 minutes to get a 1/6 chance the train will be there if alex arrives between 1.00pm to 1.20pm
we get the final answer by
=1/3( 1/6 + 1/3 + 1/3)
=5/18
So, the probability that the train will be there when Alex arrives is 5/18
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Answer:
y=10
Step-by-step explanation:
<span>Quincy
says that 3 is a good estimate for 3.4 X 0.09, is she correct? Why?
When we say estimates meaning it is not the exact answer but close to what is
the exact.
Now, if Quincy estimated 3 as the product of 3.4 * .09, then let’s check if she
has the correct estimates.
=> 3.4 estimates is 3
=> 0.09 estimates is 0.1
Now the answer is 0.3 and not 3.
Thus, Quincy’s estimate is wrong.</span>
Answer:
downwards
Step-by-step explanation:
the equation of a parabola in vertex form is
f(x) = a(x - h)² + k
where (h, k ) are the coordinates of the vertex and a is a multiplier
• if a > 0 then parabola opens upwards
• if a < 0 then parabola opens downwards
for
f(x) = - 4(x - 3)² + 9 with a = - 4 < 0 , then
the parabola opens downwards
weii ni yo entiendo esa mamada:u
