Frodo ran miles in of an hour. How many miles can Frodo run in one hour?

Leni [432]

Two or more lines are parallel when they lie in the same plane and never intersect. The symbol for parallel is ||. To mark lines parallel, draw arrows (>) on each parallel line. If there are more than one pair of parallel lines, use two arrows (>>) for the second pair. The two lines below would be labeled AB←→ || MN←→− or l || m.

For a line and a point not on the line, there is exactly one line parallel to this line through the point. There are infinitely many lines that pass through A, but only one is parallel to l.

6 0

3 years ago

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A television game show has 11 doors, of which the contestant must pick 3. Behind 3 of the doors are expensive cars, and behind

bezimeni [28]

For there to be 1 car, we consider two possible outcomes:

The first door opened has a car or the second door opened has a car.

P(1 car) = 2/6 x 4/5 + 4/6 x 2/5

P(1 car) = 8/15

For there to be no car in either door

P(no car) = 4/6 x 3/5

P(no car) = 2/5

Probability of at least one car is the sum of the probability of one car and probability of two cars:

P(2 cars) = 2/6 x 1/5

= 1/15

P(1 car) + P(2 cars) = 8/15 + 1/15

= 3/5

6 0

3 years ago

The height h(n) of a bouncing ball is an exponential function of the number n of bounces.

Digiron [165]

Answer:

The height of a bouncing ball is defined by $h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}$ .

Step-by-step explanation:

According to this statement, we need to derive the expression of the height of a bouncing ball, that is, a function of the number of bounces. The exponential expression of the bouncing ball is of the form:

$h = h_{o}\cdot r^{n-1}$ , $n \in \mathbb{N}$ , $0 < r < 1$ (1)

Where:

$h_{o}$ - Height reached by the ball on the first bounce, measured in feet.

$r$ - Decrease rate, no unit.

$n$ - Number of bounces, no unit.

$h$ - Height reached by the ball on the n-th bounce, measured in feet.

The decrease rate is the ratio between heights of two consecutive bounces, that is:

$r = \frac{h_{1}}{h_{o}}$ (2)

Where $h_{1}$ is the height reached by the ball on the second bounce, measured in feet.

If we know that $h_{o} = 6\,ft$ and $h_{1} = 4\,ft$ , then the expression for the height of the bouncing ball is:

$h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}$

The height of a bouncing ball is defined by $h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}$ .

5 0

3 years ago

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Please answer the question in the photo that I have attatched. Please also explain how to solve it so I may solve the others.

olga nikolaevna [1]

Wats Noh is solver for c

4 0

2 years ago

Can someone help me with question 6 please?

ivann1987 [24]

This is kind of a guess but (a) you have the amount not the amount per blank so it’s not frequency.
(B) work out percentages or fractions or whatever for the data I.e. terraced - 6/20 3/10 30%
(C)measure the angle you draw and if it’s more than more and less than less

5 0

3 years ago