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3 years ago

Please answer correctly !!!!! Will mark brainliest !!!!!!!!!

Mathematics

2 answers:

SVEN [57.7K]3 years ago

8 0

Answer:

y=(x-5)^2 - 6

Step-by-step explanation:

Subtracting the 5 to the x moves the parabola 5 units to the right. Putting the -6 at the end moves the parabola down 6 units.

shtirl [24]3 years ago

8 0

Answer:

$y=\left(x-5\right)^{2}-6$

Step-by-step explanation:

I graphed the original parabola and the new parabola on the graph below. I moved the original parabola down 6 and right 5.

You might be interested in

Find the area of the parallelogram

marshall27 [118]

Answer:

The answer is B

Step-by-step explanation:

To find the area of a parallelogram you need to multiply base by height

In this problem the base is 67 square ft and the height is 52 square feet 67 times 52 = 3484

6 0

3 years ago

Kendra found this relationship between the quantities in the table.

slava [35]

Answer:

Kendra should have multiplied the x-values by 75 to get the y-values

Step-by-step explanation:

Given

Table

X|| Y

1 || 75

2 || 150

3 || 225

4 || 300

5 || 375

Given that Kendra multiply x by 7.5 to get y

The relationship of x and y can be calculated as thus;

y = rx

Where y and x are the values at the y and x column respectively and r is the constant of proportionality

When y = 75, x = 1.

Plug in these values in the above formula

y = rx becomes

75 = r * 1

75 = r

r = 75

When y = 150, x = 2

150 = r * 2

Multiply both sides by ½

150 * ½ = r * 2 * ½

75 = r

r = 75

When y = 225, x = 3

225 = r * 3

Multiply both sides by ⅓

225 * ⅓ = r * 3 * ⅓

75 = r

r = 75

Notice that r remains 75 and the difference between y values is 75

If you apply these formula on when y = 300 or 375 and when x = 4 or 5, the constant of proportionality will remain The value of 75.

Hence, Kendra mistake is that; Kendra should have multiplied the x-values by 75 to get the y-values

6 0

3 years ago

Read 2 more answers

There are 11 red and blue

daser333 [38]

4 because 11-7=4 is it subtraction?

3 0

3 years ago

Read 2 more answers

Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation:

Vikentia [17]

Answer:

$\= x = 18.5$ , $\sigma = 5.15$

$15.505 < \mu < 21.495$

$14.93 < \mu < 22.069$

Step-by-step explanation:

From the question we are are told that

The sample data is 21, 14, 13, 24, 17, 22, 25, 12

The sample size is n = 8

Generally the ample mean is evaluated as

$\= x = \frac{\sum x }{n}$

$\= x = \frac{ 21 + 14 + 13 + 24 + 17 + 22+ 25 + 12 }{8}$

$\= x = 18.5$

Generally the standard deviation is mathematically evaluated as

$\sigma = \sqrt{\frac{\sum (x- \=x )^2}{n}}$

$\sigma = \sqrt{\frac{\sum ((21 - 18.5)^2 + (14-18.5)^2+ (13-18.5)^2+ (24-18.5)^2+ (17-18.5)^2+ (22-18.5)^2+ (25-18.5)^2+ (12 -18.5)^2 )}{8}}$

$\sigma = 5.15$

considering part b

Given that the confidence level is 90% then the significance level is evaluated as

$\alpha = 100-90$

$\alpha = 10\%$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table the value is

$Z_{\frac{ \alpha }{2} } = 1.645$

The margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E =1.645 * \frac{5.15 }{\sqrt{8} }$

=> $E = 2.995$

The 90% confidence interval is evaluated as

$\= x - E < \mu < \= x + E$

substituting values

$18.5 - 2.995 < \mu < 18.5 + 2.995$

$15.505 < \mu < 21.495$

considering part c

Given that the confidence level is 95% then the significance level is evaluated as

$\alpha = 100-95$

$\alpha = 5\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table the value is

$Z_{\frac{ \alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E =1.96 * \frac{5.15 }{\sqrt{8} }$

=> $E = 3.569$

The 95% confidence interval is evaluated as

$\= x - E < \mu < \= x + E$

substituting values

$18.5 - 3.569 < \mu < 18.5 + 3.569$

$14.93 < \mu < 22.069$

8 0

3 years ago

A commercial fisherman is (less likely, equally likely, more likely) to need health insurance than a supermarket employee.

Talja [164]

Answer:

A commercial fisherman is

EQUALLY LIKLEY

to need health insurance than a supermarket employee.

A person who smokes is

MORE LIKLEY

to need health insurance than a nonsmoker.

An 18-year-old male college student is

LESS LIKLEY

to need health insurance than a 72-year-old retired female.

5 0

3 years ago