(3n+2)/(n-4) - (n-6)/(n+4)
common denominator (n-4)(n+4)
{(n+4)(3n+2)-(n-4)(n-6)}/{(n-4)(n+4)}
Use the foil method:
{(3n²+14n+8)-(n²-10n+24)}/{(n-4)(n+4)}
distribute negative sign:
{(3n²+14n+8-n²+10n-24)}/{(n-4)(n+4)}
subtract:
(2n²+24n-16)/{(n-4)(n+4)}
take out 2:
2{n²+12n-8}/{(n-4)(n+4)}
Answer:
251,576
Step-by-step explanation:
first look at the them thousands place, see that it has a "5" in it, and also look for the "5" in the hundred's place
That number has 5 in both the ten-thousands, and the hundreds place and the rest don't have both.
(Hope that helps explain the brain teaser)
This question is impossible to solve.
this is why:
if 4x-4=0
then x=1
so if 8x + 4 = 8
then x is false.
I get these question quite a lot in my GCSEs.
you have to prove why they are fake.
You can see 84.78 as
.
So, you can see the problem as 
First, multiply all the numerators together and all the denominators together.
You end up with 
=33.912