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Evgen [1.6K]
4 years ago
12

Find the height of an equilateral triangle whose side measures 56 cm​

Mathematics
2 answers:
pychu [463]4 years ago
5 0

Answer:

48.5 cm

Step-by-step explanation:

For this you can use the Pythagorean theorem. You know that your hypotenuse will be 56 cm, and one side will be half of that, 28. This sets up the equation:

a^2+28^2=56^2

So, a^2 is 2,352

And a, rounded to the nearest hundredth, is 48.5 cm

Hope this helps :)

user100 [1]4 years ago
3 0

Answer: 48.5

Step-by-step explanation:

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Find the coordinates of the point (a, b).
Leviafan [203]

Answer:

a = \frac{1}{\sqrt{2} } and b = \frac{\sqrt{2} }{2}

Step-by-step explanation:

As we know, the radius of the unit circle is 1 unit (it is the hypotenuse in the right triangle, the blue line)

We use trigonometric formulas to find out a and b

  • Sin(45) = opposite side / hypotenuse

<=> Sin(45) = b / 1

<=> b= Sin(45)*1 = \frac{\sqrt{2} }{2}

  • Cos(45) = adjacent side / hypotenuse

<=> Cos(45) = a / 1

<=> a =  Cos(45)*1 = \frac{1}{\sqrt{2} }

So: a = \frac{1}{\sqrt{2} } and b = \frac{\sqrt{2} }{2}

5 0
3 years ago
Help please asappppppp! i need to get this done! will mark brainliest
postnew [5]

Answer:

C = 96.71 inches

A = 745.06 in ^2

Step-by-step explanation:

d = 30.8

The radius will be 1/2 d=   1/2 (30.8) = 15.4

The circumference = pi *d

                                 = pi * 30.8

                                  =96.761

The area = pi * r^2

                = pi * (15.4)^2

                = 745.06011

4 0
3 years ago
Please help me on this for my quiz: Which equation represents an inverse variation with a constant of 56?
Virty [35]

Answer:

D) xy/2 = 28

Step-by-step explanation:

Inverse Variation:

y = k/x

Given:

k = 56

Work:

y = k/x

y = 56/x

<u>xy = 56</u>

xy/2 = 28

xy = 28 * 2

<u>xy = 56</u>

3 0
3 years ago
A bicycle racer sprints at the end of a race to clinch a victory. The racer has an initial velocity of 10.0 m/s and accelerates
Grace [21]

Answer:

20m/s

Step-by-step explanation:

This can be solved using the acceleration / velocity equations.

Specifically,

v² = u² + 2as

Where

v = final velocity = what we need to find

u = initial velocity = given as 10.0m/s

a = acceleration = given as 0.5m/s²

s = distance = 300m

Hence,

v² = 10² + (2)(0.5) (300)

    = 100 + 300

    =400

v = √400 = 20 m/s

8 0
3 years ago
Write me an example of a unit rate
zlopas [31]
An example of a unit rate would be driving a car at 50 miles per hour. 50 miles per every 1 hour is a unit rate.
4 0
4 years ago
Read 2 more answers
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